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Phantasy [73]
3 years ago
5

5p-3r=1

Mathematics
2 answers:
melomori [17]3 years ago
6 0
To answer, multiply the first equation by 2. Then, add the equations,
                                10p - 6r = 2
                         +       8p + 6r = 4
The resulting sum would be 18p = 6. The value of p from the equation is p = 1/3. Substitute this value to either of the equation,
                                 10(1/3) - 6r = 2    ; r = 2/9
Thus, the answer is letter C. 
Brilliant_brown [7]3 years ago
4 0
If you would like to solve the system of equations, you can do this using the following steps:

5p - 3r = 1     /*2
8p + 6r = 4
__________
10p - 6r = 2
<span>8p + 6r = 4
</span>__________
10p - 6r + 8p + 6r = 2 + 4
18p = 6
p = 6/18
p = 1/3

<span>5p - 3r = 1
</span>5 * 1/3 - 3r = 1
5/3 - 3r = 1
5/3 - 1 = 3r
5/3 - 3/3 = 3r
2/3 = 3r
r = 2/9

(p, r) = (1/3, 2/9)

The correct result would be <span>(1/3, 2/9)</span>.
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How to write 19,000+400+1+60=
zloy xaker [14]

Answer: 19,461

Step-by-step explanation:

Add 19,000+400 get 19,400

Add 19,400+60 and get 19,460 add 1 and get 19,461

8 0
3 years ago
2/4 + 10/4=<br> 1<br> 3<br> 7<br> 10
eimsori [14]

Answer:

3

Step-by-step explanation:

10/4 = 2 1/2

2 1/2 + 2/4 = 3

5 0
3 years ago
Max w = 5y1 + 3y2<br> s. a.<br> y1 + y2 ≤ 50<br> 2y1 + 3y2 ≤ 60<br> y1<br> , y2 ≥ 0
CaHeK987 [17]

The maximum value of the objective function is 330

<h3>How to maximize the objective function?</h3>

The given parameters are:

Max w = 5y₁ + 3y₂

Subject to

y₁ + y₂ ≤ 50

2y₁ + 3y₂ ≤ 60

y₁ , y₂ ≥ 0

Start by plotting the graph of the constraints (see attachment)

From the attached graph, we have:

(y₁ , y₂) = (90, -40)

Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂

w = 5 * 90 - 3 * 40

Evaluate

w = 330

Hence, the maximum value of the function is 330

Read more about objective functions at:

brainly.com/question/26036780

#SPJ1

7 0
2 years ago
Which statements are true based on the diagram?
s344n2d4d5 [400]

Answer:

The answer to this is a, b, d, e

Step-by-step explanation:

Took the quiz

8 0
4 years ago
Read 2 more answers
A ball is thrown into the air with an upward velocity of 32 ft/s. Its height (h) in feet after t seconds is given by the functio
Natasha2012 [34]
For this case we have the following equation:
 h = -16t ^ 2 + 32t + 6
 Deriving we have:
 h '= -32t + 32
 We equal zero and clear t:
 -32t + 32 = 0
 32t = 32
 t = 32/32
 t = 1 s
 Then, the maximum height is given by:
 h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
 h (1) = 22 feet
 Answer:
 
It takes the ball to reach its maximum height about:
 
t = 1 s
 
The ball's maximum height is:
 
h (1) = 22 feet
6 0
4 years ago
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