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3 years ago

Can I get some help on the last question?

Mathematics

1 answer:

Bogdan [553]3 years ago

8 0

Answer:

10 & 11 are 29 and 151. 9 is vertical to 10, so it must also be 29 as defined by the first angle. 12 is supplementary to 13, so it must be the difference of 180 by 65: 115. 4 is part of a right triangle, so it must be 45. 7 is vertical to 4 and 3, so adding those angles together will be 70 degrees. By defining what 7 was we now can figure out what 6 is, angle 1 & 7 add up to 99, subtract that from 180 (b/c they're on a flat line.) You recieve 81. Finally angle 8 is supplementary from 9, stating it must be 151. (Oh yea, 14 & 15 are 115 & 65.) Sorry this took so long.

Step-by-step explanation:

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Katie is buying a refrigerator for her apartment. She's choosing between a regular fridge and a gigantic fridge . She notices th

Anuta_ua [19.1K]

Answer:

Volume of the gigantic fridge is 2.5 times the volume of regular fridge.

Step-by-step explanation:

This question is incomplete; here is the complete question.

Katie is buying a refrigerator for her apartment. She's choosing between a regular fridge and a gigantic fridge (details are shown in the table below). She notices that the gigantic fridge costs 3 times as much as the regular fridge.

How many times as great is the volume of the gigantic fridge as the volume of the regular fridge?

Area of the base, Height, Price

Regular Fridge: 1m² / 2m / $200

Large Fridge: 2m² / $\frac{5}{2}$ m / $600

In this question cost of the large fridge is 3 times as much as the regular fridge.

Area of the base of regular fridge = 1m²

Height of the regular fridge = 2m

So volume of this fridge = 1×2 = 2m³

Area of the base of the large fridge = 2m²

Height of the large fridge = $\frac{5}{2}$ m

Volume of the large fridge = $\frac{5\times 2}{2}$ = 5m³

Ratio of the volumes of the large and regular fridge = $\frac{5}{2}=2.5:1$

Therefore, volume of the gigantic fridge is 2.5 times the volume of regular fridge.

3 0

3 years ago

Please help ASAP! Only one question!!

levacccp [35]

It is negative because the plot is going down not up

5 0

3 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

2 years ago

A(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x-x-10 What is a+b?

igor_vitrenko [27]

a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10

(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)

a(x-1)+b(x-2)+x+1=9x-10

Now this equation is much simpler!

(a+b)x-a-2b+x+1=9x-10

(a+b)x-a-2b=8x-11

(a+b-8)x-a-2b-11=0

a+b-8=(a+2b-11)/x

I can't solve it 3 variables and 1 equations means infinite answers so yea.

4 0

3 years ago

What is the measure of JKL?

Orlov [11]

Answer:

Step-by-step explanation:

83 and JKL form a straight line so they add to 180 degrees

83+ JKL = 180

Subtract 180 from each side

83-83+ JKL = 180-83

JKL = 97

7 0

3 years ago

Read 2 more answers