<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
It would be 31+t.
Unless there's more to this question.
Answer:
3/4
Step-by-step explanation:
From this question we have that this team played 32 games.
They lost 8 out of these 32 games
So their total wins = 32 - 8 = 24
Therefore the fraction of their win would be = win / total number of games played
= 24/32
When reduced further
24/32 = 3/4
Therefore the fraction of games which the team won = 3/4
Thank you!
Answer:
F
Step-by-step explanation:
The area is equal to length times width.
Use the foil method to multiply (2x-5)(3x+3).
