Energy. Active transport uses energy, and passive transport does not take energy
Answer:
The correct answer will be option-C.
Explanation:
DNA polymerase is an enzyme which replicates the DNA in 5' to 3' direction as well as it performs the exonuclease activity in 3' to 5'.
This exonuclease activity increases the rate of replication with high accuracy. This mechanism of proofreading is known as a proof-reading mechanism which increases the accuracy rate of DNA synthesis by 100- fold.
Thus, Option-C is the correct answer.
Rover (or sometimes planetary rover) is a space exploration vehicle designed to move across the surface of a planet or other celestial body. Some rovers have been designed to transport members of a human spaceflight crew; others have been partially or fully autonomous robots. Rovers usually arrive at the planetary surface on a lander-style spacecraft.[1] Rovers are created to land on another planet, besides Earth, to find out information and to take samples. They can collect dust, rocks, and even take pictures. They are very useful for exploring the universe.
Answer:
Part A - Dd
Part B - 50%
Part C - Option E
Part D - dY
Part E - 50%
Part F - 50%
Explanation:
Given,
Let the allele for dominant trait (wild type) be "D" and the allele for recessive ornithine transcarbamylase deficiency (OTD) be "d"
A X-linked recessive gene affects male offspring in a family tree though a female remains a carrier until it mates with a male with the a recessive diseased allele.
Part A
Father's genotype would be Dd. Hence it will pass d gene (X diseased gene ) to her daughter.
Thus , Woman's genotype is Dd
Part B
Genotype of Normal man - DD
DD * Dd
DD, Dd, Dd, DD
One of the two males will have ornithine transcarbamylase deficiency (OTD), an X-linked recessive disorder producing mental deterioration hence, the probability is 50%
Part C
Option E is correct
Only one of the female offspring will have ornithine transcarbamylase deficiency (OTD), an X-linked recessive disorder which will be expressed if other allele is also X linked recessive.
Hence, The chance of being a carrier will be one out of two female offspring i.e 50% and and chance of having OTD is 0%
Part D
dY
Part E
dY * Dd
DY, dY, dD, dd
one out of the two female is diseased. Hence, the probability is 50%
Part F
50%
