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3 years ago

14

Thomas hiked 6 miles in Monday, 10 Thomamiles on Tuesday and 8 miles on Wednesday. Which value is closest to the mean number of

miles he hiked over three day period

1 answer:

Korolek [52]3 years ago

7 0

I think the answer is 7

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Answer for points

givi [52]

B=area of the base and 12cm
H=height and 9cm
Volume= 216cm

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2 years ago

Read 2 more answers

URGENT WILL GIVE BRAINLIEST PLZ HELP

Lorico [155]

Answer:

22000

to the test

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3 years ago

Each side of a rhombus is 6 cm. The length of the diagonals are 10 cm and 12 cm. What is the

ladessa [460]

Answer:

60cm²

Step-by-step explanation:

The area of a rhombus is: A=d1×d2/2, where d1 and d2 are its diagonals.

A=10×12/2=60cm²

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2 years ago

For X a binomial random variable with n=5 and p=1/4, answer the following

mash [69]

Recall that for $X\sim\mathrm{Bin}(n,p)$ , i.e. a random variable $X$ following a binomial distribution over $n$ trials and with probability parameter $p$ ,

$\mathbb P(X=x)=f_X(x)=\begin{cases}\dbinom nx p^x(1-p)^{n-x}&\text{for }x\in\{0,1,\ldots,n\}\\\\0&\text{otherwise}\end{cases}$

So you have

$\mathbb P(X=2)=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac34\right)^{5-2}=\dfrac{135}{512}\approx0.26$

$\mathbb P(2\le X\le4)=\displaystyle\sum_{x=2}^4\mathbb P(X=x)$
$=\dbinom52\left(\dfrac14\right)^2\left(1-\dfrac14\right)^{5-2}+\dbinom52\left(\dfrac14\right)^3\left(1-\dfrac14\right)^{5-3}+\dbinom52\left(\dfrac14\right)^4\left(1-\dfrac14\right)^{5-4}$
$=\dfrac{375}{1024}\approx0.37$

The expected value of $X\sim\mathrm{Bin}(n,p)$ is simply $np$ , while the standard deviation is $\sqrt{np(1-p)}$ . In this case, they are $\dfrac54=1.25$ and $\sqrt{\dfrac{15}{16}}\approx0.97$ , respectively.

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2 years ago

Which graph shows the solution to the inequality Negative 3 x minus 7 less-than 20

mart [117]

Answer:

qw567

Step-by-step explanation:

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2 years ago