Answer:
See below ~
Step-by-step explanation:
<u>Drawing the rectangle</u> (Refer attachment)
<u>Horizontal sides</u>
- There are two x-values present : 1 and 6
- Find the difference
- 6 - 1 = 5
- The horizontal sides of the rectangle are <u>5</u> units long
<u>Vertical sides</u>
- Two y-values are present : 4 and 5
- Find the difference
- 5 - 4 = 1
- The vertical sides of the rectangle are <u>1</u> unit long
<u>Perimeter</u>
- 2(Horizontal side + Vertical side)
- 2(5 + 1)
- 2(6)
- 12
- The perimeter of the rectangle is <u>12</u> units
Answer:
(x×11)÷52.25
Step-by-step explanation:
if 11=52.25 and y=x then x11÷52.25 i think that is the answer
9514 1404 393
Answer:
- Angle 1 = 139°
- Angle 2 = 41°
- x = 29; exterior angle = 131°
Step-by-step explanation:
These problems let you make use of the fact that the sum of the remote interior angles is equal to the exterior angle.
__
1. 53° +86° = ∠1
139° = ∠1
__
2. ∠2 +92° = 133°
∠2 = 133° -92°
∠2 = 41°
__
3. (x +9)° +93° = (4x+15)°
87 = 3x . . . . . . . . . . . . . . . . subtract x+15°
29 = x . . . . . . . divide by 3
The exterior angle is ...
(4x +15)° = (4·29 +15)° = 131° . . . exterior angle
Answer:
They multiplied the exponents instead of adding.
Step-by-step explanation:
Essentially, 2^2 x 2^3 is (2)(2) x (2)(2)(2) which is 5, not 6
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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