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Delicious77 [7]
3 years ago
7

Ken got 7 hamsters and 3 mice today. If he does not want to put more than 3 hamsters or mice in a cage, how many cages does he n

eed?
Mark as Brainliest
Mathematics
1 answer:
egoroff_w [7]3 years ago
7 0
7 + 3 = 10

10 / 3 = 3.33

He needs 4 cages.
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Step-by-step explanation:

\underline{\large{ \tt{G \: I \: V \: E \: N}}} :

  • Line a & b are parallel
  • m ∠ 8 = 150 °

\underline{ \large{ \tt{T \: O\:  \: F \: I \: N \:D}}} :

  • m ∠ 2

\underline{ \large{ \tt{S\: O \:L \: U \: T \: I \: O \: N}}} :

\large{ \tt{m  \: \angle \: 8  \:  +  \: m  \: \angle \: 2 = 180 \degree}} [ Sum of co-interior angles ]

⤑ \large{ \tt{150 \degree \:  + m  \: \angle \: 2}} = 180 \degree

⤑ \large{ \tt{m \angle \: 2 \:  =  \: 180 \degree - 150 \degree}}

⤑ \large{ \tt{m  \: \angle \: 2 \:  =  \bold{ \tt{30 \degree}}}}

\red{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \underline{ \bold{ \tt{30 \degree}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

# \underbrace{ \tt{Carry \: On \: Learning}} !!

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8 0
3 years ago
Read 2 more answers
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