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Delicious77 [7]
2 years ago
7

Ken got 7 hamsters and 3 mice today. If he does not want to put more than 3 hamsters or mice in a cage, how many cages does he n

eed?
Mark as Brainliest
Mathematics
1 answer:
egoroff_w [7]2 years ago
7 0
7 + 3 = 10

10 / 3 = 3.33

He needs 4 cages.
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All zeros of polynomial function 3x^4 +14x^2 -5
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Answer:

Correct answer:  x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

Step-by-step explanation:

Given:

3 x⁴ + 14 x² - 5 = 0   biquadratic equation

this equation is solved by a shift  x² = t and get:

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t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6

t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6

t₁ = -5   or  t₂ = 1 / 3

the solution t₁ = -5 is not accepted because it cannot be x² = -5

we accepted  t₂ = 1 / 3

x² =  1 / 3  ⇒  

x₁ = 1 / √3 = √3 / 3  or  x₂ = - 1 / √3 = - √3 / 3

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