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Svetlanka [38]
3 years ago
5

The number that occurs twice is the mode?

Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0
The number that occurs the most is the mode
cupoosta [38]3 years ago
5 0
The mode is the number that mostly shows up
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Which of the following expressions is equivalent to 14xy – 28x – 36y + 48? 2(7x – 6)(y – 2)(3y + 4) 2(7x – 6)(y – 2)(3y – 4) 2[7
Zolol [24]

The expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

<h3>Factorizing expressions</h3>

Factorization is a way of separating the equations into two separate factors.

Given the expression below;

14xy – 28x – 36y + 48

Group

(14xy – 28x) – (36y + 48)

14x(y - 2) - 12(3y-4)

Factor out the value of 2 from both terms

2[7x(y-2)-6(3y-4)]

Hence the expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

Learn more on factorization here: brainly.com/question/25829061

#SPJ1

7 0
2 years ago
Check my math work please, use photo attached
Sonja [21]

Answer:

The department total on the bottom right hand side should be 464253. Everything else is correct.

Step-by-step explanation:

Adding was wrong across the bottom row.

3 0
3 years ago
A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the
Kay [80]

Answer:  The required number of quarters in the collection is 11.

Step-by-step explanation:  Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05,   1 dime = $ 0.10   and    1 quarter = $0.25.

Then, according to the given information, we have

x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)

and

y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Comparing the values of y from equations (iv) and (v), we get

47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.

Thus, the required number of quarters in the collection is 11.

7 0
3 years ago
The measure of one acute angle in this right triangle is 45°.
maks197457 [2]

Answer:

45°

Step-by-step explanation:

90-45=45°

3 0
3 years ago
Read 2 more answers
I need help with this pls
antoniya [11.8K]
I'll explain it simply for you

1st question
Of course you know phythagoras theorm
You even wrote it up there
It states that the sum of the square of the two sides of an equilateral triangle is equal to the square of the hypotenuse
{a}^{2}  +  {b}^{2}   =  {c}^{2}
Where C is the hypotenuse
*NOTE* :
HYPOTENUSE is the greatest side in a triangle!!
And that's where your mistake is!
So you should take the greatest side as C
So in Q3. 7, 24 and 26 are the given numbers
You'll make the smaller two numbers a and b and the greatest number C
Using the Formula you'll solve the left side first which is
{a}^{2}  +  {b}^{2}
Then the right side which is
{c}^{2}

And if both are equal then it is a right triangle otherwise it isn't!
Let
a=7
b=24
c=26


a^2 + b^2
7^2 + 24^2
49 + 576 = 625
GREAT, Now the right side

26^2 = 676
Since they aren't equal it isn't a right angled triangle...

Then let
a=7.5
b=10
c=12.5

7.5^2 + 10^2
= 56.25 + 100
= 156.25



12.5^2 = 156.25

They are EQUAL
Therefore it is a right triangle too

Hopefully I helped
7 0
3 years ago
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