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ANEK [815]
3 years ago
13

A chemist has two alloys, one of which is 15% gold and 20% lead and the other which is 30% gold and 50% lead. How many grams of

each of the two alloys should be used to make an alloy that contains 82.5 g of gold and 113 g of lead?
Mathematics
1 answer:
vlabodo [156]3 years ago
6 0

Answer: 490 grams of the first alloy should be used.

30 grams of the second alloy should be used.

Step-by-step explanation:

Let x represent the weight of the first alloy in grams that should be used.

Let y represent the weight of the second alloy in grams that should be used.

A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is

0.15x and 0.2x

The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is

0.3y and 0.5y

If the alloy to be made contains 82.5 g of gold, it means that

0.15x + 0.3y = 82.5 - - - - - - - - - - - -1

The second alloy would also contain 113 g of lead. This means that

0.2x + 0.5y = 113 - - - - - - - - - - - - -2

Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes

0.03x + 0.06y = 16.5

0.03x + 0.075y = 16.95

Subtracting, it becomes

- 0.015y = - 0.45

y = - 0.45/- 0.015

y = 30

Substituting y = 30 into equation 1, it becomes

0.15x + 0.3 × 30 = 82.5

0.15x + 9 = 82.5

0.15x = 82.5 - 9 = 73.5

x = 73.5/0.15

x = 490

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Answer:

Option B

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

Let the number be n

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Answer:

Option E is correct.

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Step-by-step explanation:

Let the number of pairs of socks be x and the number pairs of shorts be y.

As per the statement:

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.

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It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.

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Multiply equation [1] by 6 both sides we get;

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Subtract equation [4] from [3] we get;

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0 is your answer

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