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3 years ago

If 50x = 500 then

Mathematics

2 answers:

harina [27]3 years ago

3 0

Answer is OD. Equals 10

lesya [120]3 years ago

3 0

Answer:

X=10

Step-by-step explanation:

Divide by 50 on both sides so ur left with X alone so 50x/50=500/50

X=10

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Sunny_sXe [5.5K]

I’m assuming a. Or 26 since it’s the only number within the range

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3 years ago

15 balls are in bag of red and blue balls if 6 is red how many red balls must be added to bag so that probability is 2÷3

Brut [27]

Answer: 12 red balls must be added

Step-by-step explanation:

Starting out with 15 balls, 6 red implies 9 blue. If blue remains 9, then we expect red to be 18 for a probability at 2/3. 18-6 = 12

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2 years ago

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2 years ago

Two liters of water are poured into an empty vase shaped like an octagonal prism. The base area is 100 square centimeters. What

Molodets [167]

Answer: Height of the water is 20 cm.

Step-by-step explanation:

Since we have given that

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Hence, height of the water is 20 cm.

4 0

3 years ago

Determine the current through each of the LEDs in the circuits below. Which LED will be

Anika [276]

a. $I = 6. 1$ × $10^-4$ A

b. $I = 2. 6$ × $10^-3$ A

c. $I = 0. 04$ A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

$I = \frac{12}{19700}$

$I = 6. 1$ × $10^-4$ A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

$I = \frac{12}{4700}$

$I = 2. 6$ × $10^-3$ A

C. V= 12V

1/R = $\frac{1}{750} + \frac{1}{1200} + \frac{1}{950 }$ = $3. 22$ × $10^-3$

R = $\frac{1}{3. 22 * 10 ^-3}$ = 310. 56 Ω

$I = \frac{12}{310. 56}$

$I = 0. 04$ A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

#SPJ1

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1 year ago