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devlian [24]
2 years ago
15

Can someone help me understand how to solve this problem?

Mathematics
1 answer:
son4ous [18]2 years ago
4 0

Answer:

Step-by-step explanation:

Multiply both sides of the equation by 10:

9x²+7x-2=0

Write 7x as a difference:

9x²+ 9x-2x -2 =0

Factor the expression:

9x x (x+1)-2x-2 = 0

9x x (x+1) - 2 (x+1) =0

Then seperate them into possible cases:

(x+1) x (9x-2) = 0

x+1 = 0

9x - 2= 0

The equation has 2 solutions:

x1 = -1

x2 = \frac{2}{9}

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A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

4 0
3 years ago
Jason and Maria are playing a board game in which three dice are tossed to determine a player's move. Find each probability for:
fredd [130]
Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216. 

P(three 5s) = (1 x 1 x 1)/216   = 1/216

P(one 5 or two 5s)  = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
6 0
3 years ago
Which expressions can be used to find the coordinates of the midpoint of PQ with endpoints P(3, –1) and Q(–7, –6)?
Tanzania [10]

Step-by-step explanation:

it is the ans of midpoint PQ

3 0
3 years ago
Suppose △LPO ≅ △HJU.<br> What is the corresponding congruent parts for each segment or angle?
SashulF [63]

Answer:

NG ( first and last letter of NBG)  = WS ( first and last letter of WTS).

BG = TS

G = S

N =W or NG = WS; BG = TS; G = S; N = W.

Step-by-step explanation:

We use the congruence statement to answer these questions.  From the way the congruence statement is written, we can see that N = W (they are in the same relative position in the congruence statement).  We also see that G and S are in the same relative position, so G = S.

Since N = W and G = S, this means that NG = WS.

From the congruence statement we can also see that B = T (they are in the same relative position).  Since G = S, this means that BG = TS.

5 0
3 years ago
This is due today pls help
umka2103 [35]

Answer: the answer is linear

Step-by-step explanation: (not sure what functions it’s talkin about but it is linear)

6 0
2 years ago
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