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kkurt [141]
3 years ago
14

I need help please and please help

Mathematics
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

whats the question and are you supposed to type in the answer or do they have a choice?

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ABCD is a quadrilateral inscribed in a circle, as shown below:
malfutka [58]

Answer:

Option 4: <u>(2x + 16)° + (x)° = 180°</u>

Step-by-step explanation:

See the attached figure.

For a quadrilateral inscribed in a circle

The opposite angles are supplementary.

So, ∠D + ∠B = 180°

From the figure:

∠B = x°  and ∠D = (2x+16)°

∴  <u>(2x + 16)° + (x)° = 180°</u>

4 0
3 years ago
PLEASE HELP WITH THIS ONE QUESTION
AveGali [126]

Answer:

step 1: move the -4 to the right: x^2 -2x = 4

step 2: add 1 to each side: x^2 -2x + 1 = 4 + 1

step 3: factor the left side and simplify the right side: (x-1)^2 = 5

step 4: take the square root of each side: x - 1 = sqr root of 5

step 5: move the 1 to the other side: x=\sqrt{5} + 1 and x = \sqrt{5} -1

6 0
2 years ago
Find the estimate of square root of 22 to teh nearest tenth using a dudne number line
Yuliya22 [10]

Answer:

Step-by-step explanation:

22 of square foot to the nearest ten is 4.6

6 0
2 years ago
Help plssssssssssssssssss
Evgesh-ka [11]

Answer:

72

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me. It's urgent​
siniylev [52]

Answer:

a) 7/5

Step-by-step explanation:

y-\frac{y-1}{2}=1-\frac{y-2}{3}  \\Through\ the\ butterfly\ method\ of\ resolving\ denominators\ ,\\\frac{2y-(y-1)}{2} = \frac{3-(y-2)}{3} \\\frac{2y-y+1}{2} = \frac{3-y+2}{3} \\\frac{y+1}{2} =\frac{5-y}{3} \\3(y+1)=2(5-y)\\3y+3=10-2y\\3y+2y=10-3\\5y=7\\y=\frac{7}{5}

5 0
3 years ago
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