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3 years ago

What’s the correct answer?

Mathematics

2 answers:

lions [1.4K]3 years ago

5 0

Short answer - yes. Proof on the screenshot below, used a graphing calculator.

Triss [41]3 years ago

4 0

Yes. akajdnskzoxjzns srry I just needed 20 characters to awnser lol

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Decrease £120 by 15%

Irina-Kira [14]

To decrease this amount by 15% we must first find out what is 15% percent.

We can do that by multiplying the decimal of 15% by 120

15% = 0.15

0.15 x 120 = 18

So 18 is 15% of 120.

Wait! that's not the answer. We are asked to decrease by 15%

So 120 - 18 = 102

Your answer is £102

6 0

3 years ago

Solve each system by substitution: {y = -x + 5, 2x + y = 11

lilavasa [31]

I hope this picture helps. I'll elaborate if needed!

5 0

3 years ago

W(t) = 3t – 1; t = 5

son4ous [18]

I’m not sure if your asking for the solution, but Hope this helps!

8 0

3 years ago

Which of these limits evaluate to 0?

Vikentia [17]

<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

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Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$

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Part III

$\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\$

7 0

3 years ago

Police estimate that 25% of drivers drive without their seat belts. If they stop 6 drivers at random, find the probability tha

Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$