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raketka [301]
4 years ago
7

2 Points

Physics
2 answers:
Papessa [141]4 years ago
5 0

Answer:

h2o

Explanation:

makvit [3.9K]4 years ago
4 0

Answer:

Archimedes principle

Explanation:

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1. What happens to a box if an astronaut pushes it in outer space
velikii [3]

Answer:it just keeps going and going for awhile

Explanation:

There is slim to no gravity in space

4 0
3 years ago
While the negatively charged rod is near the disk without touching it, a hand briefly touches the end of the post. Then the nega
Paraphin [41]

Answer:

that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

Explanation:

Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.

 

   Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.

   In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.

   If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

4 0
3 years ago
A uniform horizontal strut weighs 400.0 N. One end of the strut is attached to a hinged support at the wall, and the other end o
Olegator [25]

Answer:

Explanation:

Given

Weight of strut W_1=400 N

Weight of sign Board W_2=200 N

In this question angle which cable makes with horizontal is not given so

assuming \theta =30^{\circ}

From Diagram

Moment about hinge point

T\sin 30\times L=W_1\times \frac{L}{2}+W_2\times L

T\sin 30=\frac{W_1}{2}+W_2

T\sin 30=\frac{400}{2}+200

T=800 N

\sum F in x direction is zero

F_x=T\cos 30

F_x=800\cos 30=346.41 N

\sum F in Y direction is zero therefore

F_y+T\sin 30=W_1+W_2

F_y=400+200-800\cdot \sin 30

F_y=200 N

F_{net}\ at\ hinge=\sqrt{F_x^2+F_y^2}

F_{net}=399.99\approx 400 N                              

6 0
3 years ago
Help me answer this quick please
Reil [10]

Mass of oxygen stays the same.

8 0
3 years ago
Read 2 more answers
For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin
makvit [3.9K]

Answer: 4.675×10^-6 m

Explanation: this is a question under the pattern gotten from an interference experiment.

The formulae below defines the experiment given

y = Rmλ/d

Where y = distance between the center fringe and any other fringe in the pattern = 8cm = 0.08m

m = position of fringe = 1 ( this is because we have only one central band)

λ = wavelength of light used for experiment = 680nm = 6.8×10^-7m

d = width of slit =?

R = distance between slits and screen = 5.5 cm = 0.055m

By substituting the parameters, we have that

0.08 = 0.055 × 1 × 6.8×10^-7/d

By cross multiplying, we have that

0.08 × d = 0.055 × 1 × 6.8×10^-7

d = 0.055 × 1 × 6.8×10^-7/ 0.08

d = 3.74 × 10^-7/ 0.08

d = 46.75×10^-7

d = 4.675×10^-6 m

5 0
3 years ago
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