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3 years ago

a wave is described by where x is in meters, y is in centimeters and t is in seconds. The angular frequency is

Physics

1 answer:

Sergeeva-Olga [200]3 years ago

7 0

Complete Question

A wave is described by y(x,t) = 0.1 sin(3x + 10t), where x is in meters, y is in centimetres and t is in seconds. The angular wave frequency is

Answer:

The value is $w = 10 \ rad /s$

Explanation:

From the question we are told that

The equation describing the wave is y(x,t) = 0.1 sin(3x + 10t)

Generally the sinusoidal equation representing the motion of a wave is mathematically represented as

$y(x,t) = Asin(kx + wt )$

Where w is the angular frequency

Now comparing this equation with that given we see that

$w = 10 \ rad /s$

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3 years ago

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IceJOKER [234]

Answer:

$4.8\cdot 10^{-19} C$

Explanation:

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3 years ago

A student has a weight of 534 N. The student sits in a chair. When the student sits in a chair, how much force does the chair ap

lubasha [3.4K]

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4 years ago

A plumber is hired to plumb a house that has been renovated. In doing so the length of the pipe from the water heater to the bat

vaieri [72.5K]

As we know that the conductance is given by the formula

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3 years ago

A Ferris wheel rotating at 20 rad/s slows down with a constant angular acceleration of magnitude 5.0 rad/s2. How many revolution

IRINA_888 [86]

Answer:

It takes 6.37 revolutions to stop.

Explanation:

The constant angular acceleration is negative if we choose the wheel direction of rotation as positive direction, so radial acceleration is α=5.0 $\frac{rad}{s^{2}}$ .Because the wheel is changing its velocity and we already know radial acceleration we should use the Galileo's kinematic rotational equation:

$\omega^{2}=\omega_{i}^{2}+2\alpha\varDelta\theta$

with $\omega$ the final angular velocity (is zero because the wheel comes to rest), $\omega_{i}$ the initial angular velocity and Δθ the angular displacement. Solving (1) for Δθ :

$\varDelta\theta=\frac{\omega^{2}-\omega_{i}^{2}}{2\alpha}$

$\varDelta\theta=\frac{0-20^{2}}{(2)(-5.0)}=40rad$

The angular displacement can be converted to revolution knowing that 1 revolution is 2π rad:

$40rad=\frac{40rad}{2\pi\frac{rad}{rev}}$

$40rad=6.37 rev$

5 0

3 years ago