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Montano1993 [528]
3 years ago
10

A cylinder has a height of 1.2 cm and the following base.

Mathematics
2 answers:
netineya [11]3 years ago
7 0

Answer:

94.2 cubic mm

Step-by-step explanation:

The volume for a cylinder is

V=\pi r^2h

We can use 3.1415 for pi,

r = 5

h = 1.2

Filling in then:

V=3.1415(5^2)(1.2)

and

V=3.1415(25)(1.2) so

V=94.2mm^3

Just multiply all those numbers together.

Alex Ar [27]3 years ago
5 0

Answer:

V=942\ mm^{3}

Step-by-step explanation:

Hello

I think I can help you with this

the Volume of a cylinder is given by:

V=\pi *radius^{2} *h

in these exercises be careful with the units of measure, they must be the same units of length in this case mm

Step 1

convert 1.2 cm into mm

using a rule of three

1 cm ⇔ 10 mm

1.2 cm ⇔x mm?

\frac{1\ cm}{10\ mm}=\frac{1.2 cm}{x}\\solve\ for\ x\\\\\frac{x*1\ cm}{10\ mm}=1.2 cm\\x=\frac{1.2\ cm*10\ mm}{1\ cm} \\x=12\ mm\\

so, height is 12 mm

Step 2

put the values into the equation

Let

radius= 5 mm

height= 12 mm

V=\pi *radius^{2} *h\\V=\pi *(5\ mm)^{2} *12\ mm\\V=\pi*300\ mm^{3}\\V=942.47\ mm^{3}

Have a nice day

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Answer:

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Step-by-step explanation:

7x and 2x are the lengths

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Then you take 7 + 2 = 9

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Explain how you can compare the cost of two items that are different sizes.
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Answer:

Compare the cost for the each (smallest) unit.

Step-by-step explanation:

You can calculate the cost per unit

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4 0
2 years ago
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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

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Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

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n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

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