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Ede4ka [16]
3 years ago
11

Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8.

Mathematics
1 answer:
Gala2k [10]3 years ago
5 0
Vertex is directly in middle of directix and focus

distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice

it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
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