Which system of equations is graphed below

Mathematics

1 answer:

pychu [463]2 years ago

7 0

Hello. I could help you with this question because i'm actually learning that too. Just create another question showing the entire graph so that I could help you.

You might be interested in

Expand: ln 2a^3/b^4<br><br>Help me out cuh

Anni [7]

Answer:

$\bold {In \: 2 + 3 \: In \: {a} - 4 \: In \: {b}}$

Step-by-step explanation:

$In \bigg( \frac{2 {a}^{3} }{ {b}^{4} } \bigg) \\ \\ = In({2} {a}^{3}) - In ({b}^{4} ) \\ = In \: 2 + In({a}^{3}) - 4 \: In {b} \\ \red{ \bold{ = In \: 2 + 3 \: In \: {a} - 4 \: In \: {b} }}\\$

4 0

2 years ago

Read 2 more answers

What is the missing angle?

AleksAgata [21]

Answer:

318

Step-by-step explanation:

151+116+135+136+164+101+139=942

1260-942=318

7 0

2 years ago

Read 2 more answers

(-x to the power of 10) to the power of 2

MA_775_DIABLO [31]

Answer:

its 1 because -x(-1) raised to the 10 is -1 so raised to the 2 is 1

Step-by-step explanation:

7 0

2 years ago

Va rog e urgent am nevoie de raspuns

Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

= 2 - 1

= 1

f(√3) = 2√3 - 1

*******************************************************

$\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}$

= $\frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}$

= $\frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})$