The expression of integral as a limit of Riemann sums of given integral
is 4
∑
from i=1 to i=n.
Given an integral
.
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=
∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=![[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}](https://tex.z-dn.net/?f=%5Bn%5E%7B2%7D%28n%2B4i%29%5D%2F2n%5E%7B3%7D%2B%28n%2B4i%29%5E%7B3%7D)
∑f(a+iΔx)Δx=
∑
=4
∑
Hence the expression of integral as a limit of Riemann sums of given integral
is 4
∑
from i=1 to i=n.
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Answer:
r=3.25
Step-by-step explanation:
Answer:
94.8
Step-by-step explanation:
94.8 is the answer for 1st q
Answer:
y=3 and x=3*sqrt(3)
Step-by-step explanation:
sin(30)=y/6
1/2=y/6, y=3. As it's a right angled triangle, 6^2-3^2=x^2, x=3*sqrt(3)
The lateral area of the pyramid is 108.49 cm^2. The lateral surface area is the total of all of each side's area of a three-dimensional figure and it has a different method to calculate it. First, you must find the triangle's height by using the Pythagoras formula resulting 7.41 cm ( =squareroot(8^2-3^2)), thus, you can find the lateral area using the square and triangles area formula (108.49=(8*8) + 4*(0.5*3*7.41))<span>.</span>