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Semmy [17]
4 years ago
10

For an integrated circuit fabrication process, 1 in every 100 integrated circuits is defective on average. what is the probabili

ty that the fifth ic inspected is the first defective one found?
Mathematics
1 answer:
Ostrovityanka [42]4 years ago
5 0
1/100 is average and it’s a 1/25 chance so it’s a 1/2500
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Find the area of the figure below:
Vlad [161]

Answer:

288

Step-by-step explanation:

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3 years ago
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A coin is tossed three times. An outcome is represented by a string of the sort HTT (meaning a head on the first toss, followed
Ivanshal [37]

Answer:

Step-by-step explanation:

In this question, the sample space contains 8 elements and has been given as;

          HHT HHH THH HTH HTT TTT TTH THT

1. For event A:

Outcomes of alternating tail and head = THH HTH HTT THT

                                          = 4 outcomes

Pr(alternating tail and head (with either coming first)) = \frac{4}{8}

                                               = \frac{1}{2}

2. For event B:

Outcomes of no tails on the first two tosses = HHT HHH

                                                   = 2 outcomes

Pr (No tails on the first two tosses) = \frac{2}{8}

                                            = \frac{1}{4}

For event C:

Outcomes of a tail on both the first and the last tosses = THT TTT

                                                       = 2 outcomes

Pr(A tail on both the first and last tosses) = \frac{2}{8}

                                                = \frac{1}{4}

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3 years ago
Classify the triangle by its sides and angles
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Obtuse Scalene Triangle

Give me Brainliest if I'm correct , please ! :)

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OLYMPICS The number of men and women participating in the Winter
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Step-by-step explanation:

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3 years ago
Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As
kakasveta [241]

Answer:

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that \mu = 13.4224

Find the probability that in a day, there will be at least 1 birth.

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985


0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

7 0
3 years ago
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