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Oksana_A [137]
3 years ago
9

Angle A is circumscribed about circle O. What is the measure of angle O? 46

Mathematics
1 answer:
masya89 [10]3 years ago
5 0

Answer:

m<O = 134°

Step-by-step explanation:

OC = OB = radius of the circle

AC = AB = tangents of circle O

m<C = m<B = 90°. (Tangent and a radius always form 90°)

m<A = 46°

Therefore,

m<O = 360° - (m<C + m<B + m<A) => sum of angles in a quadrilateral.

m<O = 360° - (90° + 90° + 46°)

m<O = 360° - 226°

m<O = 134°.

Measure of angle A = 134°

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6 0
3 years ago
6. Which expression is equivalent to -21 + 28x?
Rina8888 [55]
Solution,
-28x^2+35x
take the common,
-7x(4x-5)
The answer is -7x(4x-5)
Here,
If we solve,
-7x(4x-5)
Then, the answer would be:
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Hope it helps
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3 0
3 years ago
Can you guys help please!! Due very soon!
natali 33 [55]

the y-intercept is at (0,2) where it's touching the y-axis. That's why it's called y-intercept.

Hope thishelps!

7 0
3 years ago
Read 2 more answers
The vertices of a square are A(–2, 4), B(4, 4), C(4, –2), and D(–2, –2). The diagonals of the square intersect at their midpoint
sertanlavr [38]
A(–2, 4), B(4, 4), C(4, –2), D(–2, –2)
-> select some diagonal: AC
midpoint is at A+(1/2)*AC

-> calculate vector AC:
AC=(4-(-2),-2-4)=(6,-6)
-> calculate half length of AC:
(1/2)*AC=(3,-3)

A+(1/2)*AC=
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4 0
3 years ago
Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin.
oee [108]
<h3>Answer: Triangle with the three corner points at </h3>
  • (0, 0)
  • (4, -8)
  • (-8, -8)

==================================================

Explanation:

Let's label the corner points of the triangle A,B,C starting at the origin and moving clockwise

A = (0,0)

B = (2,-4)

C = (-4,-4)

Dilating with a scale factor 2 means we multiply each coordinate of each point by the value 2

A = (0,0) becomes A' = (0,0). No change happens. This point is fixed

B = (2,-4) becomes B' = (4,-8). This point does move

C = (-4,-4) becomes C' = (-8,-8). This moves as well

So all you need to do from here is draw triangle A'B'C'.

-----------------

Side note: the lengths of triangle A'B'C' are twice as long as their counterparts on triangle ABC. Consequently, this means the perimeter of A'B'C' is twice as long as the perimeter of ABC. Also, triangle A'B'C's area is four times larger than the area of triangle ABC.

7 0
3 years ago
Read 2 more answers
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