The height of a tree is 10
10
meters long and it grows 1
1
cm in a year.
Then its height after one year = 10
10
meters 1
1
cm
Its height after 3
3
years = 10
10
meters 3
3
cm
Its height after 6
6
years = 10
10
meters 6
6
cm
Its height after x
x
years = 10
10
meters x
x
cm
Where x
x
represents an unknown number. From the last line, we can find height of the tree after a certain number of years by taking x
x
equal to that number. For example, we simply let x=15
x
=
15
, 25
25
and 55
55
. Thus, the value of x
x
depends on our choice. We can give x
x
any value or number we want. In other words, the value of x
x
is not fixed, it varies from one situation to the other. Therefore, we call x
x
a variable whereas 10
10
is a fixed number whole value does not change. So 10
10
therefore is called a constant.
Read more: http://www.emathzone.com/tutorials/basic-algebra/algebraic-expression.html#ixzz4fDkFcbpZ
Answer:
2/1
Step-by-step explanation:
20/10 devided by 10 to both numbers
Answer:
BAC=BDC(BDX)=30°
Step-by-step explanation:
We know that BD=OD.
But OD=OB= Radius of the circle.
Therefore
BD=OD=OB
BDO is equilateral triangle.
Angle DBO= 60°
Now let us take the intersecting point of CD and AB as X.
In triangle BDX,
BXD= 90°(BXD+BXC=180°, BXD+90°=180°, BXD=90°)
BXD+DBX+BDX=180°{Angle Sum Property}
90°+60°+BDX= 180°
BDX= 30°
We also know that,
BDC(BDX)= BAC (Angles lie on the same arc{BC} are equal in measure.
Therefore,
BAC=BDC(BDX)=30°
Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
