
If Ava has 34 candy bars, and each box can hold 5 bars, then we need to find out how many boxes that are filled up.

Divide the number of candy bars (34), by the number each box can hold (5)

Since we cannot have 6.8 boxes, we have to round down to 6.


To check our answer, we multiply the number of boxes (6), by the number of bars in each box (5), to get 30. We add Ava's extra bars (4), and we get the number we started off with: 34. This proves our answer is correct!
Yes and the correct one is A
Answer: 6x–y≥
–
10
Step-by-step explanation: try that
Answer:

Step-by-step explanation:
The <u>width</u> of a square is its <u>side length</u>.
The <u>width</u> of a circle is its <u>diameter</u>.
Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.
<u>Formulas</u>



If the diameter is equal to the side length of the square, then:

Therefore:

So the ratio of the area of the circle to the original square is:

Given:
- side length (s) = 6 in
- radius (r) = 6 ÷ 2 = 3 in


Ratio of circle to square:

Answer:
Any letter you want
Step-by-step explanation:
The letters used for variables don't matter. What matters is what the variables represent: their numerical value. Variables are just to help identify what needs solving. Other common variables are a, b, and c which are found frequently in trigonometry. To answer your question, there are no "next letters." You can use any letter you'd like as a variable because it holds the same numerical value. Basically, the whole alphabet is at your disposal.