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Snowcat [4.5K]
3 years ago
10

To estimate the mean number of text messages sent by cell-phone users, a researcher chooses a location on a college campus in th

e city and surveys the first 50 people who walk past. These subjects are asked how many text messages they have sent in the past 24 hours. Is it likely that bias will be present in the sample?
Possible Answers:
A:Because this is a convenience sample, it is likely that the sample results will be unbiased.

B:Because this is a convenience sample of college students, it is likely that bias is present and that the results will overestimate the mean number of text messages sent.

C:Because this is a convenience sample of college students, it is likely that bias is present and that the results will underestimate the mean number of text messages sent.

D:Because this is a voluntary response sample of college students, it is likely that bias is present and that the results will overestimate the mean number of text messages sent.
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

the answer is B :)

Step-by-step explanation:

edgen 2020

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Red and white paint are mixed to make pink paint. If the amount of red paint needed is half the amount of white paint, how many
Lady_Fox [76]

Answer:

We will need about 3.3 gallons of red paint.

Step-by-step explanation:

Let

  • r = amount of red paint
  • w = amount of white paint

The amount of red paint is half the amount of white paint.

r = 1/2 w

w = 2r [1]

We need to make a total of 10 gallons. Then,

r + w = 10 [2]

Replacing [1] in [2]

r + (2r) = 10

3r = 10

r = 3.3

We will need about 3.3 gallons of red paint.

5 0
3 years ago
Los números 4,3×-3,4× esta en progesion aritmética cuál es el cuarto termino
77julia77 [94]

Answer:  Le preguntaste a tu maestro?

Step-by-step explanation:

5 0
3 years ago
Given the graph y = f(x), explain and contrast the effect of the constant c on the graphs y = f(cx) and y = cf(x).
Igoryamba
Given the graph y = f(x)

The graph y = f(cx), where c is a constant is refered to as horizontal stretch/compression

A horizontal stretching is the stretching of the graph away from the y-axis. A horizontal compression is the squeezing of the graph towards the y-axis.  A compression is a stretch by a factor less than 1.

If | c | < 1 (a fraction between 0 and 1), then the graph is stretched horizontally by a factor of c units.
If | c | > 1, then the graph is compressed horizontally by a factor of c units.

For values of c that are negative, then the horizontal compression or horizontal stretching of the graph is followed by a reflection across the y-axis.


The graph y = cf(x), where c is a constant is referred to as a vertical stretching/compression.

A vertical streching is the stretching of the graph away from the x-axis. A vertical compression is the squeezing of the graph towards the x-axis. A compression is a stretch by a factor less than 1.

If | c | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of c units.
If | c | > 1, then the graph is stretched vertically by a factor of c units.

For values of c that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.
3 0
3 years ago
The point (1,5) lies in quadrant II of a rectangular coordinate system​
natali 33 [55]

Answer:

No

Step-by-step explanation:

Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.

Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't

6 0
3 years ago
How do you solve interquartile range?
77julia77 [94]
By Hand
Step 1: 
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: 
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: 
Place parentheses around the numbers above and below the median. 
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: 
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.

Step 5: 
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
5 0
3 years ago
Read 2 more answers
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