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adelina 88 [10]
3 years ago
7

A rectangle has side lengths of x + 3 and 2 – x. Find an expression that describes the area of the rectangle.

Mathematics
2 answers:
Rus_ich [418]3 years ago
5 0

Answer:

D


Step-by-step explanation:

We find the area of a rectangle by multiplying the lengths of both the sides <em>(length and width).</em>

  • One side given is x+3
  • Another side given is 2-x

Multiplying these 2 will give us the expression for the area of the rectangle <em>(we use distributive property given by  a(b+c)=ab+ac in this problem to multiply)</em>

Area = (x+3)(2-x)\\=2x-x^2+6-3x

<em>Now combining like terms and rearranging, we have:</em>

<em>2x-x^2+6-3x\\=-x-x^2+6\\=-x^2-x+6</em>


Answer choice D is right.


bezimeni [28]3 years ago
3 0

Answer:

D

Step-by-step explanation:

distributive property:

2x - x^2 + 6 - 3x

simplify:

-x^2 - x + 6


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2x-5y=10 ;what is the x intercept, what is the y intercept, what is the slope?
creativ13 [48]
First we put the equation in y = mx + b form where m is ur slope and b is ur y int.

2x - 5y = 10
-5y = -2x + 10
y = 2/5x - 2.......so ur slope is 2/5 and ur y int is (0,-2) <==

to find ur x int, sub in 0 for y and solve for x
2x - 5y = 10
2x - 5(0) = 10
2x = 10
x = 10/2
x = 5......and ur x int is (5,0) <==

another way to find the y int is to sub in 0 for x and solve for y...but u might as well solve it by putting it in y = mx + b form because that way u have ur slope as well.
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Answer:

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Step-by-step explanation:

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