This is the concept of numbers, given that the G.C.D two numbers (a,b)=6 and the L.C.M (a,b)=180, to find the possible number we do as follows;
L.C.M =a*b=180
since 6 is a multiple of a and b, then the numbers could be:
180/6
=30
hence these numbers could be (6,30)
Answer:
0.15 or 15%
Step-by-step explanation:
Since lengths are uniformly distributed, the probability that a class period runs between a two exact times is:

In this case, a = 47.0 and b = 52.0 minutes.
The probability that a given class period runs between 50.25 and 51.0 minutes is:

The probability is 0.15 or 15%.
What do you need help with?
Answer:
a) The formula is given by mean
the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.
b)
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
If the distribution for X is normal or if the sample size is large enough we know that the distribution for the sample mean
is given by:
Part a
The formula is given by mean
the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.
Part b
The confidence interval for the mean is given by the following formula:
Answer:
(a) 3003 ways
(b) 10897286400 ways
(c) 3002 ways
Step-by-step explanation:
Given
--- 15 players
Solving (a) Ways of selecting 10 players.
This implies combination.
So, we have:

Using:

We have:


Simplify





Solving (b) Ways of assigning positions to 10 players.
This implies permutation.
So, we have:

Using:

We have:


Solve each factorial


Solving (c) Ways of choosing at least 1 woman
We have:


Ways of selecting 10 players is: (a) 3003 ways
Since the number of men are 10, there is 1 way of selecting 10 men (i.e. selection without women)
Using complement rule:
At least 1 woman = Total - No woman

