Question

f as a function of x is equal to the square root of quantity 4 x plus 6, g as a function of x is equal to the square root of quantity 4 x minus 6 Find (f + g)(x). x times the square root of 8 4x square root of 8 times x The square root of quantity 4 times x plus 6 plus the square root of quantity 4 times x minus 6

Answer 1

Answer:

Last one

Step-by-step explanation:

The function f is:

● f (x)= √(4x+6)

The function g is:

● g(x) = √(4x-6)

Add them together:

● f+g (x)= √(4x+6 )+ √(4x-6)

Answer 2

Answer:

$\large \boxed{{\sqrt{4x+6} + \sqrt{4x-6} }}$

Step-by-step explanation:

$f(x)=\sqrt{4x+6}$

$g(x)=\sqrt{4x-6}$

$(f+g)(x)$

$f(x)+g(x)$

Add both functions.

$(\sqrt{4x+6} )+ (\sqrt{4x-6} )$