Answer:
The equation of line with given slope that include given points is                 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line . 
Since , The equation of line in slope-intercept form is 
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again 
Given as :
Slope of a line is m = - 
That include points ( 2 , 6 )
Now from the equation of line as  y = m x + c
∴   6 =  -  ( 2 ) + c
 ( 2 ) + c
Or, 6 =  -  + c
  + c
So , c = 6 +  
 
or,  c =  
 
∴   c =  
 
So, The equation of line can be written as 
  y =   -  x +
 x +  
 
Or, 3 y = - x + 20
I.e  3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is     3 y + x - 20 = 0   Answer
 
        
             
        
        
        
Answer:
x = -8 and BDC is 68 degrees.
Step-by-step explanation:
Combine -7x+12 and -8x+48 to get -15x+60.  Since BDA is a straight angle put the above equation to get -15x+60=180.  Subtract 60 from both sides to get -15x=120.  Divide -15 both sides to get -8 as your x value.  Plug in -8 to BDC, since both negatives are being multiplied, it would turn to a positive number which is 56, add 12 to get 68 as your final result for BDC.
 
        
             
        
        
        
X=15
Just divide 5x by 5 and 75 by 5
        
             
        
        
        
Answer:
x        y
−
6      1
−
5       7
/4
−
4        2
−
3       7
/4
−
2        1
Step-by-step explanation: