Answer:
The equation of line with given slope that include given points is 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line .
Since , The equation of line in slope-intercept form is
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again
Given as :
Slope of a line is m = - 
That include points ( 2 , 6 )
Now from the equation of line as y = m x + c
∴ 6 = -
( 2 ) + c
Or, 6 = -
+ c
So , c = 6 +
or, c =
∴ c =
So, The equation of line can be written as
y = -
x +
Or, 3 y = - x + 20
I.e 3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer
Answer:
x = -8 and BDC is 68 degrees.
Step-by-step explanation:
Combine -7x+12 and -8x+48 to get -15x+60. Since BDA is a straight angle put the above equation to get -15x+60=180. Subtract 60 from both sides to get -15x=120. Divide -15 both sides to get -8 as your x value. Plug in -8 to BDC, since both negatives are being multiplied, it would turn to a positive number which is 56, add 12 to get 68 as your final result for BDC.
X=15
Just divide 5x by 5 and 75 by 5
Answer:
x y
−
6 1
−
5 7
/4
−
4 2
−
3 7
/4
−
2 1
Step-by-step explanation: