Using the measurements given below, find the hypotenuse of the triangle.

Mathematics

1 answer:

zloy xaker [14]2 years ago

5 0

Answer:

In the triangle shown, AB = 11, BC = 61. Find AC. Right Triangle ABC v2. 3,600; 3,842; 60; 62. 4. Using the following measurements, find the length of the leg of the right triangle. leg = 5

Step-by-step explanation:

Not sure if that's helpful, but hope it is.

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HELP!!!! Solve x=9w−3z−15 for w. Do not write w= in your answer.

Tresset [83]

Answer:

Your answer is: x/9 + z/3 + 5/3

Isolate the variable by dividing each side by factors that don't contain the variable.

Step-by-step explanation:

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5 0

3 years ago

Jane sold 5 cakes on Monday 8 cakes on Tuesday and 7 cakes on Wednesday 3/5 of all the cakes she sold were chocolate cakes work

Triss [41]

I think its 8. im not sure

total num of cake =8+7+5
=20
num of chocolate cakes jane sold= 3/5*20
= 12
therefore num of cakes were not chocolate cake=20-12
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3 years ago

Simplify x = cos[2 arcsin(3/5)]. -7/25 7/25 4/5

Marina CMI [18]

Answer:

7/25

Step-by-step explanation:

Let $\theta= \arcsin(\frac{3}{5})$ so we have $x=\cos(2\theta)$

As $\cos(2\theta)=\cos^2\theta-\sin^2\theta$ , we'll have $\cos[2\arcsin(\frac{3}{5})]=\bigr[\cos(\arcsin(\frac{3}{5}))\bigr]^2-\bigr[(\sin(\arcsin(\frac{3}{5}))\bigr]^2$

To determine $\cos(\arcsin(\frac{3}{5}))$ , construct a right triangle with an opposite side of 3 and a hypotenuse of 5. This is because since $\theta=\arcsin(\frac{3}{5})$ , then $\sin\theta=\frac{3}{5}=\frac{\text{Opposite}}{\text{Hypotenuse}}$ . If you recognize the Pythagorean Triple 3-4-5, you can figure out that the adjacent side is 4, and thus, $\cos\theta=\frac{4}{5}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$ . This means that $\cos(\arcsin(\frac{3}{5}))=\frac{4}{5}$ .