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pashok25 [27]
4 years ago
6

Factor the given expression x squared + 16x +64

Mathematics
2 answers:
Morgarella [4.7K]4 years ago
5 0
X^2+16x+64 is a perfect square so by simply finding the square root of 64 we can factor it

The square root of 64 is 8 and as you can see 2*8 is 16 so the middle also works out

(x+8)^2 is the answer
eduard4 years ago
3 0

Answer:

(x + 8)^2.

Step-by-step explanation:

x^2 + 16x + 64

8 + 8 = 16 and 8^2 = 64 so the factors are

(x + 8)(x + 8) or (x + 8)^2

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natita [175]

In the formula of the distance between a point and a plane (not any plane but a plane parallel to the original one, equation [1] ), keeping <span>D=2</span>, and d as d itself, we get:

<span><span>D=<span><span>|a<span>x1</span>+b<span>y1</span>+c<span>z1</span>+d|</span><span>√<span><span>a2</span>+<span>b2</span>+<span>c2</span></span></span></span></span>
<span>2=<span><span><span>∣∣</span>1⋅0+2⋅0+<span>(−2)</span>⋅<span>(−<span>12</span>)</span>+d<span>∣∣</span></span><span>√<span>1+4+4</span></span></span></span>
<span><span>|d+1|</span>=2⋅3</span> => <span><span>|d+1|</span>=6</span>First solution:
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3 0
3 years ago
The bacterial strain Acinetobacter has been tested for its adhesion properties, which is believed to follow a normal distributio
pantera1 [17]

Answer:

a) Alternative hypothesis should be one sided. Because Null and Alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b) the hypothesis that mean adhesion is at least 2.66 dyne-cm is true

Step-by-step explanation:

Let μ be the mean adhesion in dyne-cm.

a)

Null and alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b)

First we need to calculate test statistic and then the p-value of it.

test statistic of sample mean can be calculated as follows:

t=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • X  is the sample mean
  • M is the mean adhesion assumed under null hypothesis (2.66 dyne-cm)
  • s is the standard deviation known  (0.7 dyne-cm_2)
  • N is the sample size(5)

Sample mean is the average of 2.69, 5.76, 2.67, 1.62 and 4.12 dyne-cm, that is \frac{2.69+5.76+2.67+1.62+4.12}{5} ≈ 3.37

using the numbers we get

t=\frac{3.37-2.66}{\frac{0.7}{\sqrt{5} } } ≈ 2.27

The p-value is ≈ 0.043. Taking significance level as 0.05, we can conlude that sample proportion is significantly higher than 2.66 dyne-cm.

Thus, according to the sample the hypothesis that mean adhesion is at least 2.66  dyne-cm is true

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3 years ago
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Answer:

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Step-by-step explanation:

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Probability that both lights will be red when she reaches them = 0.22

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Probability that the second light will be red when she reaches it = x

These are all the possible outcomes, therefore

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x = 1 - 0.55

x = 0.45

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