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2 years ago

7

BRAINLIEST Solve for X. Round to the nearest tenth.

1 answer:

erastova [34]2 years ago

3 0

X in the problem is…

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After lunch a supervisor ask you to put to a machine together before the end of the day.It is already 4hours 35second into your

Sphinxa [80]

You have 3hours 25seconds left to assemble the machine.

5 0

3 years ago

Help please will mark brainless 25 points due today

harkovskaia [24]

here's the solution,

we know that, sum of <u>measures</u> of each interior angle of a <u>triangle</u> = <u>180°</u>

<u>F</u><u>igure</u><u> </u><u>1</u><u>.</u>

=》

$40 + 32 + 9x + 9 = 180$

=》

$81 + 9x = 180$

=》

$9x = 180 - 81$

=》

$x = \frac{99}{9}$

=》

$x = 11$

<u>Figure</u><u> </u><u>2</u><u>.</u><u> </u>

=》

$42 + 63 + 4x + 15 = 180$

=》

$120 + 4x = 180$

=》

$4x = 180 - 120$

=》

$4x = 60$

=》

$x = \frac{60}{4}$

=》

$x = 15$

<u>Figure</u><u> </u><u>3</u><u>.</u>

=》

$45 + 45 + 3x - 21 = 180$

=》

$3x + 69 = 180$

=》

$3x = 180 - 69$

=》

$3x = 111$

=》

$x = \frac{111}{3}$

=》

$x = 37$

8 0

3 years ago

Read 2 more answers

X-2y = 14<br> x + 3y = 9<br> (1.12)<br> (-1,-12)<br> (12, -1)<br> (12, 1)

AleksAgata [21]

Answer:

don't know this

7 0

3 years ago

konstantin123 [22]

Answer:

θ is decreasing at the rate of $\frac{21}{16}$ units/sec

or $\frac{d}{dt}$ (θ) = $\frac{-21}{16}$

Step-by-step explanation:

Given :

Length of side opposite to angle θ is y

Length of side adjacent to angle θ is x

θ is part of a right angle triangle

At this instant,

x = 8 , $\frac{dx}{dt}$ = 7

( $\frac{dx}{dt}$ denotes the rate of change of x with respect to time)

y = 8 , $\frac{dy}{dt}$ = -14

( The negative sign denotes the decreasing rate of change )

Here because it is a right angle triangle,

tanθ = $\frac{y}{x}$ -------------------------------------------------------------------1

At this instant,

tanθ = $\frac{8}{8}$ = 1

Therefore θ = π/4

We differentiate equation (1) with respect to time in order to obtain the rate of change of θ or $\frac{d}{dt}$ (θ)

$\frac{d}{dt}$ (tanθ) = $\frac{d}{dt}$ (y/x)

( Applying chain rule of differentiation for R.H.S as y*1/x)

$sec^{2}$ θ $\frac{d}{dt}$ (θ) = $\frac{1}{x}$ $\frac{dy}{dt}$ - $\frac{y}{x*x}$ $\frac{dx}{dt}$ -----------------------2

Substituting the values of x , y , $\frac{dx}{dt}$ , $\frac{dy}{dt}$ , θ at that instant in equation (2)

2 $\frac{d}{dt}$ (θ) = $\frac{1}{8}$ *(-14)- $\frac{8}{8*8}$ *7

$\frac{d}{dt}$ (θ) = $\frac{-21}{16}$

Therefore θ is decreasing at the rate of $\frac{21}{16}$ units/sec

or $\frac{d}{dt}$ (θ) = $\frac{-21}{16}$

3 0

3 years ago

Please help me with this i need to submit it today

kaheart [24]

(3x12)+(2x19)-3-3-3-3-3 if that's not right super sorry

6 0

2 years ago