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Vaselesa [24]
3 years ago
9

2n-5=11 Two step equation

Mathematics
1 answer:
Alborosie3 years ago
4 0

Answer:

the answer is 8

Step-by-step explanation:

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Using algebra, I obtained that r=5
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A square has sides with lengths of (x - 2) units. A rectangle has a length of x units and a width of
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Answer:

(A)The area of the square is greater than the area of the rectangle.

(C)The value of x must be greater than 4

(E)The area of the rectangle is (x^2-4x) \:Square \:Units

Step-by-step explanation:

The Square has side lengths of (x - 2) units.

Area of the Square

(x-2)^2=(x-2)(x-2)=x^2-2x-2x+4\\=(x^2-4x+4) \:Square \:Units

The rectangle has a length of x units and a width of  (x - 4) units.

Area of the Rectangle =x(x-4)=(x^2-4x) \:Square \:Units

<u>The following statements are true:</u>

(A)The area of the square is greater than the area of the rectangle.

This is because the area of the square is an addition of 4 to the area of the rectangle.

(C)The value of x must be greater than 4

If x is less than or equal to 4, the area of the rectangle will be negative or zero.

(E)The area of the rectangle is (x^2-4x) \:Square \:Units

3 0
3 years ago
PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK
dem82 [27]

Answer:

\huge\boxed{9}

Step-by-step explanation:

\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}

Rule of exponents a^0 = 1 , 1/a^m = a^{-m}

=> \sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}

=> \sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}

Combining same bases

=> \sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}

When bases are same , powers are to be added

=> \sf 2 ^{-16-12+28} * 3^{10-8}

=> \sf 2^{-28+28} * 3^2

=> \sf 2^0 * 3^2

=> \sf 3^2

=> 9

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3 years ago
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My homework says, "Does the graph represent a proportional relationship? Why or why not? You MUST explain to get credit."
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Answer:

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