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polet [3.4K]
3 years ago
8

A disk, initially rotating at 130 rad/s, is slowed down with a constant angular acceleration of magnitude 3.0 rad/s2.(a) How muc

h time does the disk take to stop?
(b) Through what angle does the disk rotate during thattime?
Physics
1 answer:
Art [367]3 years ago
8 0

Answer

given,

initially rotating speed = 130 rad/s

final rotating speed = 0 rad/s

constant acceleration = 3 rad/s²

a)  using equation of rotating acceleration

   \omega_f = \omega_i + \alpha t

   0 = 130 - 3 \times t

    3 t = 130    

 t = 43.33 s

time does the disk take to stop is equal to 43.33 s

b) again using equation of rotation

    \theta = \omega_i t + \dfrac{1}{2}\alpha t^2

    \theta = 130\times 43.33 - \dfrac{1}{2}\times 3 \times 43.33^2

    \theta = 2817 rad

angle does the disk rotate during that time is equal to 2817 rad

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In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright frin
Natasha2012 [34]

Answer:

y = 0.0233 m

Explanation:

In a Young's Double Slit Experiment the distance between two consecutive bright fringes is given by the formula:

Δx = λL/d

where,

Δx = distance between fringes

λ = wavelength of light

L = Distance between screen and slits

d = Slit Separation

Now, for initial case:

λ = 425 nm = 4.25  x 10⁻⁷ m

y = 2Δx = 0.0177 m => Δx = 8.85 x 10⁻³ m

Therefore,

8.85 x 10⁻³ m = (4.25 x 10⁻⁷ m)L/d

L/d = (8.85 x 10⁻³ m)/(4.25 x 10⁻⁷ m)

L/d = 2.08 x 10⁴

using this for λ = 560 nm = 5.6 x 10⁻⁷ m:

Δx = (5.6 x 10⁻⁷ m)(2.08 x 10⁴)

Δx = 0.0116 m

and,

y = 2Δx

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<u>y = 0.0233 m</u>

3 0
3 years ago
How can humans increase the rate of endangered of extinct species
labwork [276]

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If you build and populate more zoos, some of the endangered species might not be able to survive in captivity

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5 0
4 years ago
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7 0
3 years ago
If the numbers on the plate are 6.0 cm apart, and the spy satellite is at an altitude of 160 km , what must be the diameter of t
Alexxx [7]

Answer:

The diameter of the camera aperture must be greater than or equal to 1.49m

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Let ∅ = minimum angular separation between the two objects that the satellite can resolve

tan( ∅) = x/d

Since there is minimum angular separation, tan( ∅) ≈∅

∅ = x/d

∅ = 0.06/160000

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For the satellite to be able to resolve the objects,

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7 0
3 years ago
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