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3 years ago

Find the average acceleration of a northbound subway train that slows from 12 m/s to 9.6 m/s in 0.9 s

Physics

1 answer:

o-na [289]3 years ago

6 0

2.7 m/s2 average acceleration of a northbound subway train

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Acetone is a flammable solvent used in the making of plastics. The density is 790kg/m3. to convert 790kg/m3 to g/cm3

Artist 52 [7]

Answer: 0.790 g/cm3

Explanation:

The density of acetone is 790 Kg/m3.

To convert from Kg to g we multiply by 1000 (1 Kg = 1000 g)

To convert from m3 to cm3 we multiply by 10∧6

So, The density of acetone in (g/cm3) = (790 x 1000) / (10∧6) = 0.79 g/cm3

4 0

3 years ago

Explain two scenarios where a large truck can have the same momentum as a small car.

KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

$p=mv\cdots(i)$

Let $M_L$ and $M_S$ be the masses of the large truck and the car respectively, and $V_L$ and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck $= M_LV_L$

and the momentum of the small car $= M_SV_S$ .

If the large truck has the same momentum as a small car, then the condition is

$M_LV_L=M_SV_S\cdots(ii)$

The equation (ii) can be rearranged as

$\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}$

So, the first scenario:

$\frac {M_L}{M_S}=\frac {V_S}{V_L}$

$\Rhghtarrow M_L:M_S=V_S:V_L$

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

$\frac{M_L}{V_S}=\frac{M_S}{V_L}$

$\Rhghtarrow M_L:V_S= M_S:V_L$

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0

3 years ago

Ask Your Teacher In Example 24.6, we found that the electric field of a charged disk approaches that of a charged particle for d

Ulleksa [173]

Answer: E = 7394.6N/C

Explanation:

Please find the attached file for the solution

8 0

3 years ago

the speed of a tortoise and a hare are 1m/s and 3m/s. the mass of hare is 5kg and the tortoise is 20kg. which has greater moment

Novosadov [1.4K]

Answer: tortoise

Explanation:

Given the following :

Speed of tortoise = 1m/s

Speed of hare = 3m/s

Mass of hare = 5kg

Mass of tortoise = 20kg

Momentum = product of Mass and velocity

Momentum of hare = mass of hare × Velocity of hare

Momentum of hare = 5kg × 3m/s = 15kgm/s

Momentum of tortoise = mass of tortoise × Velocity of tortoise

Momentum of tortoise = 20kg × 1m/s = 20kgm/s

Therefore, tortoise has a greater momentum than hare.

8 0

4 years ago

a blank is the small number to the lower right of the chemical symbol. It tells how many atoms of the element are present in the

victus00 [196]

The answer is subscript

4 0

4 years ago