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Sergeu [11.5K]
3 years ago
5

Peter added the following fractionsIs Peter correct?

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:i think it would most likely be c

Step-by-step explanation:

since you can only add denominators when they are the same number


NikAS [45]3 years ago
8 0
I think the answer is c
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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.8 parts
Alexxandr [17]

Answer:

The value of the test statistic is t = 2.67

Step-by-step explanation:

The null hypothesis is:

H_{0} = 7.8

The alternate hypotesis is:

H_{1} \neq 7.8

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem, we have that:

X = 8.2, \mu = 7.8, \sigma = 0.6, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{8.2 - 7.8}{\frac{0.6}{\sqrt{16}}}

t = 2.67

The value of the test statistic is t = 2.67

5 0
3 years ago
The length of a rectangle is 5 inches more than it's width, x. The area of a rectangle can be represented by the equation.x^2+5x
Digiron [165]

Answer:

the width=15; the length=20

Step-by-step explanation:

1. to solve the given equation: x²+5x-300=0;

x₁= -20; x₂=15, where 'x' can be only positive value. It means x=15;

2. according to the condtition the length is more, it means 15+5=20.

3. the width is x=15; the length is 20.

8 0
3 years ago
Pls help! I dont have much time left :(
kaheart [24]

Answer:

Please don't cheat on your map test. These are very important for your school, I know that lots of kids dont like school but I hate to be a party pooper. You can reportthis answer since its not a answer.

Step-by-step explanation:

6 0
3 years ago
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Elena L [17]
Your answer would be
he needs .4 Liters of milk

Hope this helps :)

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3 years ago
Simplify the expression.<br><br> 55−4⋅5+12
Lunna [17]
Your answer is 62.5. Hope i helped
4 0
3 years ago
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