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Sergeu [11.5K]
3 years ago
5

Peter added the following fractionsIs Peter correct?

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:i think it would most likely be c

Step-by-step explanation:

since you can only add denominators when they are the same number


NikAS [45]3 years ago
8 0
I think the answer is c
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What is the solution to these equations y= 2x +1 and x +2y= 27
Llana [10]

Answer:

The first one is -1/2

the second one is x+2y-27=0

5 0
3 years ago
Chen completed the division problem below.
alekssr [168]

<u>Answer:</u>

B. He multiplied the dividend by 100 instead of 10.

<u>Step-by-step explanation:</u>

Chen had to divide 1.926 by 0.9. To make it easier to divide, he thought of multiplying both the dividend and the divisor by 10.

Chen multiplied the divisor by 10 but mistakenly multiplied the dividend by 100 instead of 10.

So his whole division problem was changed.

Therefore, the correct answer option is B. He multiplied the dividend by 100 instead of 10.

6 0
3 years ago
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The school cafeteria sells 300 half-pints Of milk everyday. How many gallons of milk is that?
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7 0
3 years ago
Hello again. if someone gives me a hand with this book thickness excercise please thanks
geniusboy [140]

Answer:

Known:

• a book have front, back and 200 pages

• front= 0.7 mm

• back= 0.7 mm

• each page= 0,14 mm

ask:

calculate the minimum thickness...?

answer:

a. 200 p × 0,14 = 28 mm

b. front + back = 0.7+0.7= 1.4 mm

Thickness= 28+1,4 = 29,4 mm

I hope this helps

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8 0
4 years ago
I’m need this worked out step by step by tonight
Pie

9514 1404 393

Answer:

  -3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

  -7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

  -14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

  -9 ≤ 3x ≤ 19

Divide all parts by 3.

  -3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

  |(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

__

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

  |f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

  |f(x)| > g(x)   ⇒   f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

8 0
3 years ago
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