We are given that the
coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)
To solve this problem, we must plot this on a graphing paper or graphing
calculator to clearly see the movement of the graph. If we transform this by
doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)
And the final
transformation is translation by 3 units left and 2 units down. This can still
be clearly solved by actually graphing the plot. The result of this
transformation would be:
<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>
Answer:
A. 
Step-by-step explanation:
We have that, ΔABC is transformed to get ΔA''B''C''.
We see that the following transformations are applied:
1. Reflection across x-axis i.e. flipped across x-axis.
Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.
2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.
So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.
Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.
I believe it's increasing on all fronts, because if you start from the right, you see that the y values always increase, hence they are increasing. They do it for when x<0 and when x>0. So, it should be increasing on all real numbers