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lora16 [44]
3 years ago
14

-10=-14v+14? Not sure

Mathematics
2 answers:
Talja [164]3 years ago
8 0
-24=-14v
24=14v
24/14=v
12/7=v
satela [25.4K]3 years ago
7 0
-1.714 is your answer
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Not too sure about this one
elena-s [515]

Answer:

see explanation

Step-by-step explanation:

let y = f(x), then

y = 11x - 1

Interchange x and y and solve for y

x = 11y - 1 ( add 1 to both sides )

x + 1 = 11y ( divide both sides by 11 )

y = \frac{x+1}{11}, hence

f^{-1}(x) = \frac{x+1}{11}

3 0
3 years ago
Use zero property to solve the equation.<br> F(x)=3x(x+7)-2(x+7)
oksian1 [2.3K]

Answer:

x = -7 or x = 2/3

Step-by-step explanation:

I'm assuming you meant solve for x when f(x) = 0.

f(x) = 3x(x + 7) - 2(x + 7)

0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them

x + 7 = 0 or 3x - 2 = 0 -- Use ZPP

x = -7 or x = 2/3 -- Solve

7 0
3 years ago
Which value of the x is in the solution set of the following inequality -x+8&gt;6
vfiekz [6]
The answer would be 1
7 0
3 years ago
Jenny is having a party. She has one
seropon [69]
2 .............:)
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4 0
3 years ago
45. For customers generating their own solar power, ZG&amp;E charges them $3 per month per kilowatt (kWh) for excess electricity
uranmaximum [27]

(A) The customer that owns a 3-kW system exports 120 kWh monthly to the grid will have the following bills for both companies:

For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

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For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

\$20+(120kWh\times\frac{\$0.06}{1kWh})=\$27.2

(B) The customer that owns a 5-kW system exports 300 kWh monthly to the grid will have the following bills for both companies:

For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

300kWh\times\frac{\$3}{1kWh}=\$900

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

\$20+(300kWh\times\frac{\$0.06}{1kWh})=\$38

4 0
1 year ago
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