On a number line what is the distance between -12 and 20

Can someone please help me with my homework <br> Ignore the bottom question

pav-90 [236]

1. x = 1 2. x = -30 3. x = -2 4. x = 15 5. x = 7, y = 11 6. x = 4, y = 1

7. x = 1/2, y = 25/5 8. x = 1/4, y = 11/2

hope this helps :3

6 0

3 years ago

find an equation for the nth term of the sequence. -3, -12, -48, -192, ... select one: a. an = 4 • -3n 1 b. an = -3 • 4n - 1 c.

Andrews [41]

$-3;-12;-48;-192;...\\\\It's\ the\ geometric\ sequence:a_n=a_1r^{n-1}\\\\a_1=-3;\ a_2=-12\\\\r=a_2:a_1\to r=-12:(-3)=4\\\\\boxed{a_n=-3\cdot4^{n-1}}\to\fbox{b.}$

3 0

3 years ago

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Please help!!!

k0ka [10]

Answer:

The following property: If a = b and b = c, then a = c. One of the equivalence properties of equality. Note: This is a property of equality and inequalities.

Congruent Angles have the same angle (in degrees or radians). That is all. These angles are congruent. They don't have to point in the same direction. They don't have to be on similar sized lines.

The segment addition postulate states that if we are given two points on a line segment, A and C, a third point B lies on the line segment AC if and only if the distances between the points meet the requirements of the equation AB + BC = AC.Jan 4, 2016

The (interior) bisector of an angle, also called the internal angle bisector (Kimberling 1998, pp. 11-12), is the line or line segment that divides the angle into two equal parts. The angle bisectors meet at the incenter.

Step-by-step explanation:

4 0

3 years ago

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Bourne Incorporated reports a cash balance at the end of the month of $2,520. A comparison of the company's cash records with th

lianna [129]

Answer:

Company balance$2,170

Service fees: $(67)

NSF check: $(170)

Note received: 1,100

Interest earned: 17

Reconciled company balance: $3,050

Step-by-step explanation:

5 0

2 years ago

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PLEASE HELP.

OverLord2011 [107]

Answer:

Explicit formula for

1) $a_n=17-3(n-1)$

2) $a_n=(\frac{1}{2} )^{n-1}\cdot 20$

Step-by-step explanation:

W have to find the first few terms of the given sequence and then find an explicit equation

Explicit formula = f(n) + d(n-1) , where,

f(n) is first term,

d is common difference,

n-1 is one term less than the term number.

1)

Given : $a_1=17\\\\a_{n+1}=a_n-3$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

2)

Given : $a_1=20\\\\a_{n+1}=\frac{1}{2} \cdot a_n$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

$\text{We put n =1, we get,}\\\\\\a_2=\frac{1}{2} \cdot a_1=\frac{1}{2} \cdot 20=10=(\frac{1}{2} )^{2-1}\cdot 20\\\\\\\text{We put n =3, we get,}\\\\\\a_4=\frac{1}{2} \cdot a_3=\frac{1}{2} \cdot 5=\frac{5}{2}=(\frac{1}{2} )^{4-1}\cdot 20\\\\\\$

Thus, we obtained an explicit formula,

$a_n=(\frac{1}{2} )^{n-1}\cdot 20$

8 0

3 years ago

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