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Vikki [24]
3 years ago
13

The price of a ticket was increase from 50p to 60p. What is the increase a as a fraction in its simple form? As a percentage of

the original price?
Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
5 0
10p or 20% was added on
insens350 [35]3 years ago
4 0

Given is the price increase of a ticket from 50p to 60p.

Using the concept of fractions, we can find the ratio of new price to old price as follows :-

\frac{new \;\; price}{old \;\; price} = \frac{60p}{50p} =\frac{6}{5}

So the increase in price is \frac{6}{5} times old price of the ticket.

Using the formula of percentage, we can find the percentage change in price as follows :-

Percentage = \frac{(new\;\;price \;-\; old\;\;price) }{old \;\; price}*100 \\\\ Percentage = \frac{60p-50p}{50p}*100 \\\\ Percentage = \frac{10p}{50p}*100 \\\\ Percentage = 20\;\%

Hence, Percentage increase is 20% of the original price.

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Heather finished the 12-kilometer race in 2 hours. If Heather kept her pace constant, what was her rate? A. 24 km/hr. B. 14 km/h
andriy [413]

Answer: D, 6km/hr.

Step-by-step explanation:

Heather can finish a 12-kilometer race in 2 hours, and now we have to find how many kilometers she can ride/run at in 1 hour.

How many hours can Heather run in 1 hour? To solve that, we can use the equation 12 ÷ 2.

12 ÷ 2 = 6.

Therefore, if Heather keeps her pace constant, then her rate will be 6km/hr, or D.

7 0
3 years ago
A professor at a university wants to estimate the average number of hours of sleep the students get during exam week. The profes
balandron [24]

Answer:

The sample size is n = 2

Step-by-step explanation:

From the question we are told that

   The margin of error is  E =4.266

    The standard deviation is  \sigma = 2.539

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  2.58

Generally the sample size is mathematically represented as  

   n = [\frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ] ^2

=>  n = [\frac{2.58  *  2.539  }{4.266} ] ^2

=>  n = 2

6 0
2 years ago
I need help on this question​
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
An employment agency specializing in temporary construction help pays heavy equipment operators $138 per day and general laborer
prisoha [69]

Answer:

L = 2,

O = 31

Step-by-step explanation:

First using the givens, write out some formulas.

Heavy equipment operators = O

General laborers = L

  • O + L = 33
  • 138O + 87L = 4044

Now use substitution, it doesn't matter which one you substitute.

  • O = -L +33
  • 138( -L + 33 ) + 87L = 4044

Distribute and solve for L.

  • -138L + 4554 + 87L = 4044
  • -138L - 87L = 4044 - 4554
  • -225L = -510
  • L = -510/-225
  • L = 2

L = 2, meaning number of laborers employed is 2.

Now plug 2 = L into one of the original equations.

  • O + L = 33
  • O + 2 = 33
  • O = 33 - 2
  • O = 31

O = 31, meaning number of heavy equip. operators employed is 31.

4 0
3 years ago
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