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Lisa [10]
3 years ago
9

In a box containing 20 cans, 12 of the cans contain vegetables. In the box, 5 of the cans are dented, with 2 of the dented cans

containing
vegetables
What is the probability that a randomly selected can in the box is dented or contains vegetables?
OA 65%
OB. 75%
OC. 95%
OD 85%
Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer: B.) 75%

Step-by-step explanation:

12 cans contain veggies and 5 cans are dented, since two of the dented cans contain veggies don't count those two. This means you'll add 12 and 3 which equals 15. 15 out of 20 is an example of three fourths or 75%.

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Each lap around a park is 1 1⁄5 miles. Kellyn plans to jog at least 7 1⁄2 miles at the park without doing partial laps. How many
Nitella [24]
1 1/5 can be written as 6/5
7 1/2 can be written as 15/2
Let X be the number of laps Kellyn wants to jog to meet her 7 1/2 mile goal:
6/5x = 15/2                Multiply both sides by (5/6), the inverse of 6/5
x = 15(5) / 2 ( 6) 
x = 75 / 12
X = 25 / 4, or 6 and 1/4 laps

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3 years ago
In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60
Olegator [25]

Answer:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

Step-by-step explanation:

Data provided

\bar X=7.38 represent the sample mean for the fuel efficiencies

\mu population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size  

Confidence interval

The formula for the confidence interval of the true mean is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom for this case is given by:

df=n-1=601-1=600

The Confidence level for this case is 0.95 or 95%, and the significance level \alpha=0.05 and \alpha/2 =0.025 and the critical value is given by t_{\alpha/2}=1.96

Replcing into the formula for the confidence interval is given by:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

8 0
3 years ago
What fraction of a year are 31 days ?
Alborosie

9514 1404 393

Answer:

  • non-leap years: 31/365
  • leap years: 31/366

Step-by-step explanation:

As a fraction of the number of days in a calendar year, it will depend on whether the year is a leap year.

non-leap years have 365 days, so 31 days is 31/365 years.

leap years have 366 days, so 31 days is 31/366 years.

_____

If you're asking for the purpose of computing interest, you need to be aware that "ordinary interest" counts 360 days in a year. 31 days would be 31/360 years. "Exact interest" counts 365 days in a year, so 31 days would be 31/365 years.

In astronomy, the definitions of "day" and "year" may vary, depending on the frame of reference and what direction in space marks the boundary of the period. The precise fraction will depend on how you define these terms and where the clock is located.

5 0
2 years ago
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