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Rashid [163]
3 years ago
14

What is the point-slope form of the equation for the line with a slope of -2 that passes through the point (4,-6)

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
6 0

Answer:

y + 6 = -2 (x-4)

Step-by-step explanation:

Point-slope formula is represented by the equation y-y_1 = m (x-x_1). When knowing a point a line crosses through and its slope, you can write an equation in this form. Substitute the m, x_1, and y_1 for real values.

The m represents the slope of the line. Since we know the slope is -2, substitute -2 for m. The x_1 and y_1 represent the x and y values of the point the line passes through. Since the line passes through (4, -6), substitute 4 for x_1 and -6 for y_1. This gives the following answer and equation:

y-(-6) = -2 (x - (4))\\y + 6 = -2 (x-4)

viva [34]3 years ago
3 0

Answer:

y=-2x+2

Step-by-step explanation:

y-y1=m(x-x1)

y-(-6)=-2(x-4)

y+6=-2(x-4)

y=-2x+8-6

y=-2x+2

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The center of a circle is 5 units below the origin, and the radius is 10 units. what is the equation of the circle?
levacccp [35]

Answer:

x² + (y + 5)² = 100

Step-by-step explanation:

If the center of the circle is 5 units below the origin, its x coordinate is 0 and its y-coordinate is -5. So, the center of the circle is at (0, -5).

Using the equation of a circle with center (h, k)

(x - h)² + (y - k)² = r² where r = radius of the circle.

Given that r = 10 units, and substituting the values of the other variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - 0)² + (y - (-5))² = 10²

x² + (y + 5)² = 100

which is the equation of the circle.

6 0
3 years ago
Read 2 more answers
Divide. 1/4 ÷ 3=<br>help​
Aleonysh [2.5K]
1/4/3 = 1/12
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6 0
3 years ago
1/6d + 2/3 = 1/4(d-2)
xxMikexx [17]
D = 14

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4 0
3 years ago
Solving Exponential and Logarithmic Equation In exercise,solve for x or t.See example 5 and 6.
Aloiza [94]

Answer:

0.70275

Step-by-step explanation:

Data provided in the question:

4e²ˣ⁻¹ -1 = 5

now solving for 'x'

⇒ 4e²ˣ⁻¹ = 5 + 1

or

⇒ 4e²ˣ⁻¹ = 6

or

⇒ e^{(2x-1)} =\frac{6}{4}

or

⇒ e^{(2x-1)} =\frac{3}{2}

now,

taking natural log both sides, we get

⇒ 2x - 1 = \ln(\frac{3}{2})

also,

we know

⇒ \log(\frac{A}{B}) = \log(A)+\log(B)

thus,

⇒ 2x - 1 = ln(3) - ln(2)

or

⇒ 2x - 1 = 1.0986 - 0.6931

or

⇒ 2x - 1 = 0.4055

or

⇒ 2x = 0.4055 + 1

or

⇒ 2x = 1.4055

or

⇒ x = 0.70275

3 0
3 years ago
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