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3 years ago

Please answer this correctly

Mathematics

1 answer:

Dafna11 [192]3 years ago

7 0

Allies is 4:2
Brookes is 2:1
The answer is they are equivalent because you see if you would double brookes it would equal allies and if you divided allies by 2 you would get brookes

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Step-by-step explanation:

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3 years ago

Suppose x is a normally distributed random variable with a mean of 22 and a standard deviation of 5. The probability that x is l

MaRussiya [10]

Answer:

The probability that x is less than 9.7 is 0.0069 = 0.69%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 22, \sigma = 5$

The probability that x is less than 9.7 is _____.

This is the pvalue of Z when X = 9.7. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{9.7 - 22}{5}$

$Z = -2.46$

$Z = -2.46$ has a pvalue of 0.0069

The probability that x is less than 9.7 is 0.0069 = 0.69%

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4 years ago

About 1/5 of all adults in the United States have type O blood. If four randomly selected adults donate blood, find the probabil

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Answer:

We know that:

1/5 = 0.2 of all adults in US have type O blood.

Then: 4/5 = 0.8 of all adults in US do not have type O blood.

a) All four are type O.

Let's think this, as four events with two possible outcomes, having type O blood, with a probability of 0.2, and not having type O blood with a probability of 0.8

Now if we want the four people to have type O blood, then we have the outcome with probability 0.2 four times, and as we know, the joint probability is equal to the product of the individual probabilities:

P =0.2^4 = 0.0016

b) None of them is type O.

Similar to the above case, but this time we work with four times the probability 0.8

P = 0.8^4 = 04096

c) Two of the four are type O.

Here we will have two times the probability 0.2, and two times the probability 0.8.

p = 0.2^2*0.8^2

But, if the people is ordered, the two persons with type O blood can be:

first and second

first and third

first and fourth.

second and third

second and fourth

third and fourth.

6 different combinations, then the actual probability for this case will be:

P = 6*p = 6*(0.2^2*0.8^2) = 0.1536

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Step-by-step explanation:

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