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Viktor [21]
3 years ago
13

Ralph read 1/8 of his book. what fraction of the book does he still have left to read?​

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

Ralph still needs to read 7/8

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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

6 0
3 years ago
What is the true solution to ln 20+ln 5= 2 ln x
Aleks [24]
Ln20+ln5=2lnx
ln(20x5)=lnx^2
ln100=1nx^2
100=x^2
square root
x=10
5 0
3 years ago
Read 2 more answers
Can someone help me with this question in so confused
Svetlanka [38]

Answer:

D(1, 2) → D'(2, 7)

E(-3, -5) → E'(-10, 0)

F(4, -1) → F'(11, 4)

Step-by-step explanation:

D(1, 2) → D'   ________

Translate image (3x - 1, y + 5)

(1, 2), x = 1 and y = 2

3x - 1 = 3(1) - 1 = 3 - 1 = 2

y + 5 = (2) + 5 = 7

E(-3, -5) → E' ________

(-3, -5), x = -3 and y = -5

3x - 1 = 3(-3) - 1 = -9 - 1 = -10

y + 5 = (-5) + 5 = 0

F(4, -1) → F'   ________

(4, -1), x = 4 and y = -1

3x - 1 = 3(4) - 1 = 12 - 1 = 11

y + 5 = (-1) + 5 = 4

3 0
1 year ago
You are designing a container in the shape of a cylinder. The radius is 6 inches. You want the container to hold at least 324π c
goldfiish [28.3K]
Answer: 9 inches

Explaination: The volume of a cylinder, V = (πr^2)H, so H = V/(πr^2).

Using the parameters you specified, H = 324π/[(π)(6^2)] = 324π/36π = 324/36 = 9 inches
4 0
3 years ago
Researcher Sandy Beach found a correlation coefficient of +2.3 between variables X and Y. She is thrilled because that correlati
tia_tia [17]
Correlation coefficient is always between -1 and +1. So it cannot be +2.3
7 0
2 years ago
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