Which number would go in first second and third place in a number line? The numbers are 0.1, 0.01, and 1.00

If two out of every three balls in a multi color package is pink how many balls in a package of 21 balls will be pink

LuckyWell [14K]

Answer:

14 balls will be pink out of 21 balls.

Step-by-step explanation:

Given that:

2 out of every 3 balls are pink in a multi color package.

Ratio of pink balls to balls drawn = 2:3

Number of balls in package = 21 balls

Number of pink balls = x

Ratio = x:21

This is a proportional relationship

2 : 3 :: x : 21

Product of mean = Product of extreme

3x = 21*2

3x = 42

Dividing both sides by 3

$\frac{3x}{3}=\frac{42}{3}\\x=14$

Hence,

14 balls will be pink out of 21 balls.

3 0

3 years ago

RSM QUESTION NEED HELP!!!!!! A biker traveling at his usual speed can go from his house to work in 4 hours. When the weather is

kogti [31]

<h3>Answer: 216 miles</h3>

=======================================

Work Shown:

d = distance from work to his house

x = speed when weather is good

y = speed when weather is bad

y = x-6 since he travels 6 mph slower

------------------------

On a good weather day, he travels for 4 hours and goes at x mph

distance = rate*time

d = r*t

d = x*4

d = 4x

----------------------

On a bad weather day, he travels 4.5 hours (half hour more than 4 hrs) and goes at y = x-6 mph

d = r*t

d = y*4.5

d = 4.5y

d = 4.5(x-6) .... replace y with x-6

d = 4.5x-27 .... distribute

----------------------

The values of d for both equations are the same, as the biker is traveling the same distance. So we can equate the two right hand sides (RHS) and solve for x.

4.5x-27 = 4x

4.5x-4x = 27

0.5x = 27

x = 27/0.5

x = 54

The biker's speed on a good weather day is 54 mph.

A bad weather day's speed would be y = x-6 = 54 - 6 = 48 mph.

----------------------

Now compute the value of d

d = 4x

d = 4*54

d = 216

The biker travels 216 miles on a good weather day

or,

d = 4.5*y

d = 4.5*48

d = 216

the biker travels that same distance on a bad weather day.

3 0

4 years ago

Point A is at (-7,-7) and point B is at (-5,5). What is the midpoint of line segment AB?

nevsk [136]

Answer:

MP= (-6,-1)

Step-by-step explanation:

midpoint formula: $(\frac{x^{1}+x^{2} }{2})(\frac{y^{1} + y^{2} }{2} )=MP$

(-7,-7) ( $x^{1}$ , $y^{1}$ )

(-5,5) ( $x^{2}$ , $y^{2}$ )

$(\frac{-7+-5}{2}) \\ (\frac{-7+5}{2})$ = -7+-5/2= -12/2= -6

-7+5/2= -2/2= -1

6 0

3 years ago

Complete the standard form of the equation of a hyperbola that has vertices at (-10, -15) and (70, -15) and one of its foci at (

Elena L [17]

Answer:

$\frac{(x-30)^{2}}{40^{2}} - \frac{(y+15)^{2}}{3^{2}} = 1$

Step-by-step explanation:

The equation of the horizontal hyperbola in standard form is:

$\frac{(x-k)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1$

The position of its center is:

$C(x,y) = \left(\frac{-10 + 70}{2}, -15 \right)$

$C(x, y) = (30,-15)$

The values for c and a are respectively:

$a = 70 - 30$

$a = 40$

$c = 30 - (-11)$

$c = 41$

The remaining variable is computed from the following Pythagorean identity:

$c ^{2} = a^{2} + b^{2}$

$b = \sqrt{c^{2}-a^{2}}$

$b = \sqrt{41^{2}-40^{2}}$

$b = 3$

Now, the equation of the hyperbola is:

$\frac{(x-30)^{2}}{40^{2}} - \frac{(y+15)^{2}}{3^{2}} = 1$

3 0

3 years ago

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Describe the pattern in your own words:;1;8;27;64;125 and write down the next five terms

Ipatiy [6.2K]

Answer:

the next five terms are 216,343,512,729,1000

8 0

2 years ago

Read 2 more answers