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inessss [21]
3 years ago
12

15x ( 7 - 5y ) + 3 ( 5y - x ) - ( 4x + 3 ) ( 5y - 2 )​

Mathematics
2 answers:
olga2289 [7]3 years ago
5 0

Answer:

110x-95xy+6

Explanation:

15x ( 7 - 5y ) + 3 ( 5y - x ) - ( 4x + 3 ) ( 5y - 2 )

expand:

105x-75xy+15y-3x-\left(4x+3\right)\left(5y-2\right)

simplify:

105x-75xy+15y-3x-(20xy-8x+15y-6)

open the brackets:

-20xy+8x-15y+6+102x-75xy+15y

110x-75xy-20xy+15y-15y+6

final answer:

110x-95xy+6

Sedbober [7]3 years ago
4 0
15x ( 7 - 5y) + 3 ( 5y - x) - ( 4x + 3) (5y - 2) = -95xy + 110x + 6 is your solution hope it helps :)!
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In a random sample of 25 ​people, the mean commute time to work was 33.9 minutes and the standard deviation was 7.2 minutes. Ass
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Answer:

33.9-1.32\frac{7.2}{\sqrt{25}}=31.999    

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So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

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And replacing we got:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=33.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=7.2 represent the sample standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

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Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,24)".And we see that t_{\alpha/2}=1.32

Now we have everything in order to replace into formula (1):

33.9-1.32\frac{7.2}{\sqrt{25}}=31.999    

33.9+1.32\frac{7.2}{\sqrt{25}}=35.801    

So on this case the 80% confidence interval would be given by (31.999;35.801)

And the margin of error is given by:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}}

And replacing we got:

ME = 1.32\frac{7.2}{\sqrt{25}} =1.9008

   

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