Answer:
cosjk = √55 i/3
tanjk = 8/√55 i
Step-by-step explanation:
Given
sin jk = 8/3
According to SOH CAH TOA
Sin theta = opposite/hypotenuse = 8/3
Opposite = 8
hypotenuse = 3
Get the adjacent using the pythagoras theorem
hyp² = opp²+adj²
adj² = hyp² - opp²
adj² = 3² - 8²
adj² = 9-64
adj² = -55
adj = √-55
adj = √55 i (i = √-1)
Get cosjk
cosjk = adj/hyp
cosjk = √55 i/3
Get tanjk
tanjk = opp/adj
tanjk = 8/√55 i
To find the length of the light pole you'll have to use the sine ratio.
sin 30 = x/43
43 (sin 30) = x
21.5 = x
Hope this helps :)
Answer:
A
Step-by-step explanation:
sin A=(opposite side)/hypotenuse=a/c
cos A=(adjacent side)/hypotenuse=b/c
tan A=(opposite side)/(adjacent side)=a/b
Answer:
x = 46, y = 67
Step-by-step explanation:
x = ∠ AEC = 46 ( alternate angles )
Since Δ ACE is isosceles then the base angles are congruent, then
y = 
= 
= 67
