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Romashka-Z-Leto [24]
3 years ago
7

Which fraction is equal to 3/6 HELP!

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

A 1/2

Step-by-step explanation:

You might be interested in
Plz another one help
shutvik [7]

Answer:

-17

Step-by-step explanation:

-2^3 - 3^2

= -8 - 3^2

= -8 - 9

= -17

8 0
3 years ago
Read 2 more answers
Find a101 of the sequence 5,8,11,
guajiro [1.7K]

Answer:

305

Step-by-step explanation:

This sequence es the sum of 3

5+3 =8

8+3 = 11

then

101 = 100 + 1

the fisrt date is 5

the another 100:

100*3 = 300

300 + 5 = 305

3 0
3 years ago
What is the answer to the following problem:<br> 1+1
Elanso [62]

Answer: 2

Step-by-step explanation:

add the 1 to the other 1 and it equals 2

4 0
3 years ago
Read 2 more answers
Find the balance in an account after 8 years if $500 is invested at 7% interest compounded annually
Talja [164]

Answer: 280

Step-by-step explanation:

??/500=7/100

7x500/100

35/500=7/100

35x8=280

I think this is the answer.

8 0
3 years ago
A construction company employs two sales engineers. Engineer 1 does the work of estimating cost for 70% of jobs bid by the compa
netineya [11]

Answer:

Engineer 1

Step-by-step explanation:

Based on the information given:

P( 1 ) = 0.7

P( 2 ) = 0.3

P(A | B) is a conditional probability: the likelihood of event A occurring given that B is true.

P( E | 1 ) = 0.02

P( E | 2 ) = 0.04

Then P( E | 1 ) is the probability that an error occurs when engineer 1 does the work and P( E | 2 ) is the probability that an error occurs when engineer 2 does the work.

To have an idea of which engineer is more likely to do the work when an error occurs you need to calculate P( 1 | E ) and P( 2 | E ), The probability that engineer 1 does the work when an error occurs and the probability that engineer 2 does the work when an error occurs.

The Bayes's theorem states:

P( B | A ) = \frac{P( A | B )*P( A )}{P( B )}

Using the notation above:

P( 1 | E ) = \frac{P( E | 1 )*P( 1 )}{P( E )}

P( E ) = 0.7*0.02 + 0.3*0.04 = 0.026 /// the probability that engineer 1 does the work and an error occurs or the probability that engineer 2 does the work and an error ocurrs.

P( 1 | E ) = \frac{0.04*0.3}{0.026}=0.538

Doing the same for engineer 2:

P( 2 | E ) = \frac{0.04*0.3}{0.026}=0.462

6 0
3 years ago
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