Answer:
dP/dt = 650t = 650(2 ) = 1,300 people/year
The rate of increasing of population at the end of the year 1992 is 1,300 people/year
Step-by-step explanation:
Given;
Population function as;
P(t) =325 t^2 + 28547
The rate of change of the population dP/dt at any given time can be given as;
Rate = change in population/change in time = dP/dt
dP/dt = 2×325t = 650t
Therefore, after 1992;
t = 1992-1990 = 2years
dP/dt = 650t = 650(2 ) = 1,300 people/year
The rate of increasing of population at the end of the year 1992 is 1,300 people/year
Answer:
153
Step-by-step explanation:
i = square root of -1
i = √-1
(3+12√-1) (3-12√-1)
√a times √b = √ab
a√b times c√d = (a times c) √ (b times d)
9 - (36√-1) + (36√-1) - (144(√-1)^2) =
9 - 0 - (144 * -1) =
9 - 0 - (-144) =
9 - (-144) =
9 + 144 =
153
*** funny thing is if you put
(3+12i) (3-12i)
in a calculator
it works!
it gives you the answer 153
another way:
Expand the expression using
(a-b) (a+b) =
a²-b² :
3²-(12i)²
Simplify using exponent rule with same exponent
(a*b)^n =
a^n*b^n:
3²-12²* i²
Calculate the power:
9-144* i²
Rewrite by definition
i²=-1:
9–144×(−1)
Calculate the product or quotient: 9+144
Calculate the sum or difference: 153
Answer: 153
gathmath
Answer:
x^6 +2x^5 -6x^4 +3x^2 +6x-18
Step-by-step explanation:
f(x) = x^2 +2x-6
g(x) =x^4 +3
We are going to multiply them
f(x) * g(x)= (x^2 +2x-6)(x^4 +3)
First (x^2 +2x-6)(x^4) = x^6 + 2x^5 -6x^4
Then x^2 +2x-6)(3) = 3x^2 +6x-18
----------------------------------------------
x^6 +2x^5 -6x^4 +3x^2 +6x-18
Answer:
-4x-3y+3z
Step-by-step explanation:
(-5x-3y)-(-x-3z)
-5x+x-3y+3z
-4x-3y+3z