2 answers:
Answer:
4x² + 6xy + 2y²
Step-by-step explanation:
Given
(2x + y)(2x + 2y)
Each term in the second factor is multiplied by each term in the first factor, that is
2x(2x + 2y) + y(2x + 2y) ← distribute both parenthesis
= 4x² + 4xy + 2xy + 2y² ← collect like terms
= 4x² + 6xy + 2y²
Answer: 4x^2 + 6xy + 2y^2
Step-by-step explanation:
(2x + y)(2x + 2y) =
2x*2x + 2x*2y + y*2x + y^2y =
4x^2 + 4xy + 2xy + 2y^2 =
4x^2 + 6xy + 2y^2
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