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3 years ago

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When this 3 digit number is rounded to the nearest hundred it rounds to 900. The digit in the ones is the fifth odd number you c

ount beginning with one. The sum of the digits is 22. What is the number?

1 answer:

garri49 [273]3 years ago

3 0

859....9 is the 5th odd and you know the number is in the 800s so just add 9 and 8 and subtract from 22 and you get 5

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Need help fast right now. Find the surface area of each solid. Round to the nearest tenth of necessary.

Mice21 [21]

Answer:

5)surface =2(lb*bh*hl)

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=2(48+16+48)

=2(96+16)

=2*112

=224inc^2

6)surfacearea=2*pi*r(r+h)

=2*3.14*2(2+1)

=6.28*2*3

=6.28*6

=37.68m^2

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2 years ago

What is a fraction between -3/4 and -1/3

Yuki888 [10]

let's firstly convert both fractions with the same denominator, by simply <u>multiplying each fraction by the other's denominator</u>, let's proceed.

$\bf -\cfrac{3}{4}\cdot \cfrac{3}{3}\implies \boxed{-\cfrac{9}{12}}~\hfill -\cfrac{1}{3}\cdot \cfrac{4}{4}\implies \boxed{-\cfrac{4}{12}} \\\\[-0.35em] ~\dotfill\\\\ \boxed{-\cfrac{9}{12}}~~,~~\stackrel{-\frac{2}{3}}{-\cfrac{8}{12}}~~,~~-\cfrac{7}{12}~~,~~\stackrel{-\frac{1}{2}}{-\cfrac{6}{12}}~~,~~-\cfrac{5}{12}~~,~~\boxed{-\cfrac{4}{12}}$

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3 years ago

Read 2 more answers

Looking for a step by step explanation for this question! I take the Math QRAS Accuplacer soon and practicing my math skills but

Liula [17]

The answer is 56 cookies because i did math in my head

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2 years ago

Miles bought a 10 ounce bag of chips. He wants to know if it's really 10 ounces, so he uses a scale and makes four measurements.

photoshop1234 [79]

The weight seems like most accurate to me, even thought you didn't show me what type of measurement he took.

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3 years ago

Which expression is equivalent to a^m divide a^n?(20points)

Citrus2011 [14]

<h3><u>Answer</u> :</h3>

$\bigstar\:\boxed{\bf{\dfrac{a^m}{a^n}=a^{m-n}}}$

<h3><u>Learn More</u> :</h3>

$\dag\sf\:\:a^m\times a^n=a^{m+n}$

$\dag\sf\:\:\dfrac{a^m}{a^n}=a^{m-n}=\dfrac{1}{a^{n-m}}$

$\dag\sf\:\:a^{-m}=\dfrac{1}{a^m}$

$\dag\sf\:\:(a^{m})^n=a^{mn}$

$\dag\sf\:\:a^1=a$

$\dag\sf\:\:a^0=1$

$\dag\sf\:\:\sqrt[n]{a^m}=a^{\frac{m}{n}}$

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3 years ago