Answer:
m∡GHI = 21°
Step-by-step explanation:
Since the lines are intersecting, GHI and JHK are opposite angles, so they are the same measure.
That means you can set them equal to each other
x + 7 = 3x - 21
x = 14
Now plug x into GHI
14 + 7 = 21
m∡GHI = 21°
The amount he should sell for one bottle of the fizzy juice to make the 60% profit is 22 Penny.
<h3>Cost of each juice</h3>
Orange : Lemonade
3 : 5
After buying 2 liters of orange juice and 3 liters of lemonade, cost of each;
Increase the ratio to form divisible by 2 and 3; (L.C.M of 2 and 3 = 6)
(3 x 6L) : (5 x 6L)
18L : 30L
total fizzy juice = 18L + 30L = 48 liters
bottle of orange = (18 L ÷ 2 L) = 9 bottles
bottle of lemonade = (30 L ÷ 3L ) = 10 bottles
cost of orange = 9 x £1.20 = £10.8
cost of lemonade = 10 x £1.50 = £150
Total cost = £10.8 + £150 = £25.80 = 2580 P
<h3>Total bottles that will make 48 liters fizzy juice</h3>
250 mL = 0.25 L
0.25L(n) = 48 L
n = 48/0.25
n = 192 bottles
<h3>Cost of each bottle in Penny</h3>
cost = 2580 P/192
cost = 13.44 P
<h3>Amount each bottle should be sold to make a profit of 60%</h3>
A = 100%(initial cost) + 60%(initial cost)
A = 160%(initial cost)
A = 1.6(initial cost)
A = 1.6 x 13.44 P
A = 21.5 P ≈ 22 P
Learn more about profit here: brainly.com/question/1078746
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The less coefficient in front of x^2, the wider graph
the smallest coefficient is 1/5 , so the widest graph is y=(1/5)x²
Given that <span>Henry divided the town into eight regions and randomly chose 10 households from each region in order to survey about traffic concerns. This type of sample is called</span> stratified sampling.
Stratified sampling<span> is a type of </span>sampling <span>method where</span><span> the researcher divides the population into separate groups, called strata and then, a probability </span>sample<span> (often a simple random </span>sample<span> ) is drawn from each group.</span>
Given : Angle < CEB is bisected by EF.
< CEF = 7x +31.
< FEB = 10x-3.
We need to find the values of x and measure of < FEB, < CEF and < CEB.
Solution: Angle < CEB is bisected into two angles < FEB and < CEF.
Therefore, < FEB = < CEF.
Substituting the values of < FEB and < CEF, we get
10x -3 = 7x +31
Adding 3 on both sides, we get
10x -3+3 = 7x +31+3.
10x = 7x + 34
Subtracting 7x from both sides, we get
10x-7x = 7x-7x +34.
3x = 34.
Dividing both sides by 3, we get
x= 11.33.
Plugging value of x=11.33 in < CEF = 7x +31.
We get
< CEF = 7(11.33) +31 = 79.33+31 = 110.33.
< FEB = < CEF = 110.33 approximately
< CEB = < FEB + < CEF = 110.33 +110.33 = 220.66 approximately
